averages Model Questions & Answers, Practice Test for ssc chsl tier 1

ssc chsl tier 1 SYLLABUS WISE SUBJECTS MCQs

Number Systems

Percentages

Averages

Profit & Loss

Question :16

Nine numbers are written in ascending order. The middle number is the average of the nine numbers. The average of the first five larger numbers is 68 and that of five smaller numbers is 44. What is the sum of all nine numbers?

Answer: (b)

Since, 5th term = average of 9 numbers = x

Sum of first five larger numbers = 68 × 5 = 340

Sum of first five smaller numbers = 44 × 5 = 220

Average of nine numbers = ${340 + 220 - x}/9$

(since, x is subtracted because 5th term repeated twice)

∴ $x = {560 - x}/9$

⇒ 9x + x = 560 ⇒ x = 56

∴ Sum of 9 numbers = 56 × 9 = 504

Question :17

In 1919, W. Rhodes, the Yorkshire cricketer, scored 891 runs for his country at an average of 34.27; in 1920, he scored 949 runs at an average of 28.75; in 1921, 1329 runs at an average of 36.70. What was his county batting average for the four years?

Answer: (a)

Find out the number of innings in each year.

Then the answer will be given by:

$\text"Total runs in 4 years"/\text"Total innings in 4 years"$ (4270/119 = 35.88)

Question :18

Find the average weight of four containers, if it is known that the weight of the first container is 100 kg and the total of the second, third and fourth containers' weight is defined by f (x) = $x^2 – 3/4 (x^2)$ where x = 100

Answer: (c)

Put x = 100 to get the weight of the containers.

Use these weights of find average weight as 2600/4 = 650.

Question :19

The average of five numbers is 281. The average of the first two numbers is 280 and the average of the last two numbers is 178.5. What is the third number ?

Answer: (b)

Assume the third number = x

According to question

2 × 280 + x + 178.5 × 2 = 281 × 5

or, 560 + x + 357 = 1405

or, x + 917 = 1405

or, x = 1405 - 917 = 488

Question :20

The average marks in English subject of a class of 24 students is 56. If the marks of three students were misread as 44, 45 and 61 of the actual marks 48, 59 and 67 respectively, then what would be the correct average?

Answer: (e)

Correct average

= ${(24 × 56) + (48 + 59 + 67) - (44 + 45 + 61)}/24$

= ${1344 + 174 - 150}/24 = 1368/24$ = 57

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