profit and loss Model Questions & Answers, Practice Test for ssc chsl tier 1 2023

Answer: (c)

Let the original price of each article = Rs. 100

∴ new price = Rs. 105

Original selling price of 100 articles = 100 × 100 = 10,000

Selling price of the article at new price = 97.5×105

= Rs. 10237.50

[No of article sold = 97.5]

∴ Profit = 10237.50 – 10,000 = 237.50

∴% profit = $({237.50}/{10000} × 100) $% = 2.4%

Answer: (d)

Let the SP of the article be Rs. x

Expenses = 15% of x = Rs. 0.15x

Profit = 10% of x = Rs. 0.10x

CP = Rs. 9 (given)

Therefore, 9 + 0.15x + 0.1x = x ⇒ x = 12

∴ % increase for marked price = ${12 - 9}/9 × 100$

= $100/3%$

Answer: (b)

80 : 9 = 105 : x or x = $({9 × 105}/80)$ = 11.81

Hence, S.P. per k.g = Rs. 11.81.

Answer: (b)

Let cost of 1 table be Rs. x and cost of 1 chair be Rs. y.

4x + 5y = 1000 ... (i)

Table Chair CP 4x 5y SP 1 44x 4x 1 10 10 æ ö ç ÷ + = è ø 1 5y 1 6y 5 æ ö ç ÷ + = è ø Q

SP – CP = Profit

∴ $({44x}/10 - 4x)$ + 6y – 5y = 120

${4x}/10 + y = 120$ ... (ii)

From equations (i) and (ii),

x = Rs. 200

Answer: (b)

Suppose the cost price of the goods is Rs. 100.

Then, selling price in the first case = $100(120/100)$ = Rs.120

Therefore, marked price = Rs. 120 $(100/{100 - 10})$ = Rs. $400/3$

Now, selling price in the second case

= $400/3({100 - 20}/100)$ = Rs. $320/3$

Therefore, % profit = $320/3$ - 100 (CP = 100)

= $20/3 = 6{2}/3$ %