percentage Model Questions & Answers, Practice Test for ssc cgl tier 2
If the numerator of a fraction is increased by 500% and the denominator is increased by 300%, the resultant fraction is 2$4/7$. What was the original fraction?
Answer: (a)
Let the original fraction be $x/y$.
Then, ${x + 5x}/{y + 3y} = 2{4}/7$
${6x}/{4y} = 18/7$
$x/y = 72/42 = 12/7$
$1/2$ of 3842 + 15% of ? = 24499
Answer: (c)
$1/2$ of 3842 + 15% of ? = 2449
$1921 + x + 15/100 = 2449$
$x × 15/100$ = 2449 - 1921
$x = {528 × 100}/15$ = 3520
If a% of a + b% of b = 2% of ab, then what percent of a is b ?
Answer: (c)
${a × a}/100 + {b × b}/100 = 2/100 ab$
$a^2 + b^2 = 2ab$
$a^2 + b^2 – 2ab$ = 0
$(a – b)^2$ = 0
a = b
∴ a is 100% of b
The expenditure of a household for a certain month is Rs. 20,000, out of which Rs. 8,000 is spent on education, Rs. 5,900 on food, Rs. 2,800 on shopping and the rest on personal care. What percentage of expenditure is spent on personal care?
Answer: (a)
Total Expenditure = 2000 Rs.
Education Expenditure = 8000
Food Expenditure = 5900
Shopping Expenditure = 2800
Personal care Expenditure
= 20000 – (8000 + 5900 + 2800)
= 20000 – 16700 = 3300 Rs.
Percentage of expenditure on personal care
= $\text"Personal care expenditure"/\text"total expenditure" × 100$
= $3300/2000 × 100 = 16.5%$
∴ Option (b) is correct.
In a certain examination there were 2500 candidates, of them 20% are girls and the rest boys. Suppose 5% of boys and 40% of girls failed. The percentage of candidates who passed was
Answer: (c)
Number of girls = ${2500 × 20}/100$ = 500
Number of boys = 2000
Number of fail boys = ${2500 × 5}/100$ = 100
Number of fail girls = ${500 × 40}/100$ = 200
Total no. of pass students = 2500 – 300 = 2200
Pass % = $2200/2500 × 100$ = 88%
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