averages Model Questions & Answers, Practice Test for ssc cgl tier 2
Abhay’s age after six years will be three-seventh of his father’s age. Ten years ago, the ratio of their ages was 1 : 5. What is Abhay’s father’s age at present?
Answer: (c)
Let the ages of Abhay and his father 10 years ago be x and 5x years respectively. Then,
Abhay's age after 6 years
= (x + 10) + 6 = (x + 16) years.
Father's age after 6 years
= (5x + 10) + 6 = (5x + 16) years.
∴ (x + 16) = $3/7$(5x + 16)
⇔ 7 (x + 16) = 3 (5x + 16)
⇔ 7x + 112 = 15x + 48
⇔ 8x = 64 ⇔ x = 8.
Hence, Abhay's father's present age
= (5x + 10) = 50 years.
Find the average of the following set of scores. 965, 362, 189, 248, 461, 825, 524, 234
Answer: (b)
Required average
= ${965 + 362 + 189 + 248 + 461 + 825 + 524 + 234}/8$
= $3808/8 = 476$
The mean weight of 150 students in a class is 60 kg. The mean weight of boys is 70 kg and that of girls is 55 kg, what is the number of boys in the class ?
Answer: (c)
Total weight of 150 students
= 150 × 60 = 9000 kg
Let total no. of boys = x
No. of girls = 150 – x
Average weight = ${x × 70 +(150 - x)55}/150$
⇒ 60 = ${70x + 150 × 55 - 55x}/150$
⇒ 60 × 150 = 15x + 150 × 55
⇒ 15x = 60 × 150 – 150 × 55
∴ $x = 750/15 = 50$
∴ No. of boys in the class = 50
There are five boxes in a cargo hold. The weight of the first box is 200 kg and the weight of the second box is 20% higher than the weight of the third box, whose weight is 25% higher than the first box's weight. The fourth box at 350 kg is 30% lighter than the fifth box. Find the difference in the average weight of the four heaviest boxes and the four lightest boxes.
Answer: (b)
The weight of the boxes are 1st box → 200, 3rd box → 250 kg, 2nd box → 300 kg, 4th box → 350 and 5th box → 500 kg.
Hence difference between the heavier 4 and the lighter 4 is 300.
Hence, difference in the averages is 75.
A school has 4 section of Chemistry in Class X having 40, 35, 45 and 42 students. The mean marks obtained in Chemistry test are 50, 60, 55 and 45 respectively for the 4 sections. Determine the overall average of marks per student
Answer: (b)
Required average marks
= ${40 × 50 + 35 × 60 + 45 × 55 + 42 × 45}/{40 + 35 + 45 + 42}$
= ${2000 + 2100 + 2475 + 1890}/162$
= $8464.9997/162$ = 52.25
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