clocks mcq questions answers Model Questions & Answers, Practice Test for ibps rrb so officer sclae 2 3 single exam 2024

Answer: (d)

Since, in one hour, two hands of a clock coincide only once, so, there will be value.

Required time T = $2/{11}$ (H × 30 + A°) minutes past H.

Here H = initial position of hour hand = 3 (Since 3 o'clock)

A° = required angle = 0° (Since it coincides)

T = $2/{11}$ (3 × 30 + 0) minutes past 3

= 16$4/{11}$ minutes past 3.

Answer: (c)

1st of month was Tuesday, hence the date on first Saturday was 5th.

Hence the other Saturdays of the month are 12, 19, 26. Rama met her brother on 26th.

Answer: (b)

17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)

Odd days in 1600 years = 0

Odd days in 300 years = (5 × 3) ≡ 1

97 years has 24 leap years + 73 ordinary years.

Number of odd days in 97 years = (24 × 2 + 73) = 121 = 2 odd days.

Jan. Feb. March April May June

(31 + 28 + 31 + 30 + 31 + 17) = 168 days

= 24 weeks = 0 odd day

Total number of odd days = (0 + 1 + 2 + 0) = 3

Given day is Wednesday.

Answer: (a)

Time between 1 p.m. on Tuesday to 1 p.m. on Thursday = 48 hrs. The watch gains (1 + 2) = 3 minutes in 48 hrs.

it gains 1 min, in 16 hrs.

Hence, it will show correct time at 5 a.m. on Wednesday.

Answer: (c)

No. of days between 21st July, 1947 and 21 st July, 1999 = 52 years + 366 days.

= 13 leap years + 39 ordinary years + 366 days

= (13 × 2) odd days + 39 odd days + 2 odd days

= (26 + 39 + 2) odd days = 67 odd years = 4 odd days.

= (7 – 4) = 3 days before the week day on 21st July, 1999 = Saturday.