puzzle test Model Questions & Answers, Practice Test for ibps po prelims

Answer: (b)

The sum of the numbers in each column is 200.

∴ Missing number = 200 – (87 + 56 + 50) = 7.

Answer: (b)

Putting A = 1, B = 2, C = 3, ......., M = 13, ....., X = 24,

Y = 25, Z = 26, we have :

In the first column, F – A = 6 – 1 = 5 = E.

In the second column, W – J = 23 – 10 = 13 = M.

∴ In the third column, missing letter

= O – K = 15 – 11 = 4 = D.

Answer: (d)

As, crosswise –

43 + 10 = 74,

6 3 + 10 = 226,

1 3 + 10 = 11,

3 3 + 10 = 37.

Similarly, 2³ + 10 = 18

5² + 10 = 135

Answer: (b)

The number inside the triangle is obtained by dividing the product of the numbers outside of the triangle by 10. Thus,

In I triangle, (5 × 6 × 4) ÷ 10 = 12

In II triangle, (6 × 7 × 5) ÷ 10 = 21

∴ In III triangle, missing number

= (4 × 8 × 10) ÷ 10 = 32.

Answer: (c)

Clearly, (1st row)² + (2nd row)² + (3rd row)² = 4th row.

Thus, in the first column, 4² + 2² + 1² = 21.

In the second column, 5² + 3² + 8² = 98.

∴ In the third column, missing number

= 6² + 7² + 3² = 36 + 49 + 9 = 94.