sequence test Model Questions & Answers, Practice Test for ibps po mains

Directions:

Among A, B, C and D, B is heavier than A and C but C is taller than him. D is not as tall as C while A is shortest. C is not as heavy as A. D is not as tall as C while A is shortest. C is not as heavy as A. D is heavier than B but shorter than him.

Question :21

Who is the tallest?

Answer: (c)

C is the taller.

Question :22

Who is the heaviest?

Answer: (b)

Here we have to find heaviest one, so we’ll ignore the height.

B is heavier than A and C

B > A and C

C is not as heavy as A

A > C

D is heavier that B

D > B

From the above relations we can conclude

D > B > A > C

D is the heaviest .

Question :23

P, Q, R and S are four males. P is the eldest in the group but he is not the poorest. R is the richest but not the eldest, Q is elder than S but he is not the eldest, Q is elder than S. How can the four persons be arranged in descending order of their age and money?

Answer: (c)

PRQS, RSPQ

Question :24

In a row of 35 children, M is 15th from the right end and there are 10 children between M and R. What is R's position from the left end of the row?

Answer: (a)

If we observe the question clearly, we notice that there are two possible cases

In one case, R might be right of M and in another case, R might be left of M.

If R is towards the right side of M, then it will be in 5th position from the right end.

Position of R from L.H.S = 35 + 1 – 5 =31st

If R is towards the left side of M, then it will be on 25th position from the right end.

Position of R from L.H.S = 35 +1 – 25 =11th

Since R can be either 31st or 11th position from the left end. Option (d) is the correct option.

Question :25

In a row of 25 children facing South, R is 16th from the right end and B is 18th from the left end. How many children are there between R and B?

Answer: (e)

To determine the number of people between B and R, = Total number of people – ( B's position + R's position ) =25 – ( 18 + 16 ) = - 9

Since the number of people can never be negative. Let us find out the position of B and R from the other end.

Position of R from L.H.S = Total number of students + 1 – Position of R from R.H.S = 25 + 1 – 16 = 10

Position of B from the R.H.S = Total number of students + 1 – Position of B from L.H.S = 25

+ 1 – 18 = 8

Number of students between B and R = Total number of students – ( B's position + R's position )

= 25 – ( 10 + 8 )

= 7

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