puzzle test Model Questions & Answers, Practice Test for ibps po mains

Answer: (d)

In fig. (A), (6 × 3) + (5 × 15) = 18 + 75 = 93.

In fig. (C), (4 × 8) + (18 × 1) = 32 + 18 = 50.

∴ In fig. (B), missing number

= (9 × 6) + (7 × 5) = 54 + 35 = 89.

Answer: (a)

4 × √25 = 4 × 5 = 20

27 × √9 = 27 × 3 = 81

11 × √? = 44 = ⇒ √? = $44/11$ = ⇒ ? = 16

Answer: (b)

The number inside the circle is equal to the difference between the sum of the numbers at the extremities of the horizontal diameter and the sum of numbers at the extremities of the vertical diameter.

In fig. (A), (5 + 6) – (7 + 4) = 0

In fig. (B), (7 + 6) – (8 + 4) = 1.

∴ In fig. Answer (c)

missing number

= (11 + 2) – (0 + 2) = 11

Answer: (b)

Answer: (c)

In the first row, 72 ÷ $(24/2)$ = 6.

In the second row, 96 ÷ $(16/2)$ = 12.

Let the missing number in the third row be x.

Then, 108 ÷ $(x/2)$ = 18

⇒ $x/2$ = $108/18$ = 6 ⇒ x = 12