percentages Model Questions & Answers, Practice Test for ibps clerk prelims 2023

Question :6

The population of a town is 198000. It increases by 7% in the 1st year and decreases by 5% in the 2nd year. What is the population of the town at the end of 2 years?

Answer: (a)

Population of the town after 2 years

= $198000(1 + 7/100)(1 - 5/100)$

= ${198000 × 107 × 95}/{100 × 100}$ = 201267

Question :7

35 percent of a number is two times 75 percent of another number. What is the ratio between the first and the second number respectively ?

Answer: (e)

Let the two number be x and y.

35% x = 2 × 75% y

35% x = 150% y

$35/100 × x = 150/100 × y$

35x = 150y

$x/y = 150/35 = 30/7$

x : y = 30 : 7

Question :8

52% of 666 + ? = 500

Answer: (d)

$666 × 52/100 + ? = 500$

∴? = 500 – 346.32 = 153.68

Question :9

Due to fall in manpower, the production in a factory decreases by 25%. By what per cent should the working hour be increased to restore the original production?

Answer: (b)

Decrease in production is only due to decrease in manpower.

Hence, manpower is decreased by 25%

Now, suppose that to restore the same production, working hours are increased by x%

Production = Manpower × Working hours

= M × W (say)

Now, M × W = (M – 25% of M) × (W + x% of W)

or, M × W = $75/100 M × {100 + x}/100 $W

or, 100 × 100 = 75 (100 + x)

or, $400/3$ =100 + x

∴$x = 100/3 = 33{1}/3$ %

Question :10

There are five boxes in a cargo hold. The weight of the first box is 200 kg and the weight of the second box is 20% higher than the weight of the third box, whose weight is 25% higher than the first box. The fourth box of 350 kg is 30% lighter than the fifth box. The difference in average weight of the four heaviest boxes and the four lightest boxes is :

Answer: (a)

Weight of the I st box = 200 kg

Therefore, weight of 3rd box = 250 kg,

Weight of 2nd box = 300 kg and

Weight of 4th box = 350 kg

Thus, weight of 5th box = 500 kg

∴ Average weight of four heaviest boxes

= $1400/4$ = 350kg

and average weight of four lightest boxes

= $1100/4$ = 275kg

Required difference = 75 kg

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