algebraic expressions Model Questions & Answers, Practice Test for ibps clerk prelims 2023

Answer: (b)

Let the original number of sweets be x.

According to the question

$x/{140}-x/{175}=4$

or, 175x – 140x = 4 × 140 × 175

or, x=${4×140×175}/35$=2800

Answer: (c)

Let the positive integer be x.

Now, $x^2$ – 20x = 96

or, $x^2$ – 20x – 96 = 0

or, $x^2$ – 24x + 4x – 96 = 0

or, x(x – 24) + 4 (x – 24) = 0

or, (x – 24)(x + 4) = 0

or, x = 24, – 4

x ≠ – 4 because x is a positive integer

Answer: (d)

Percentage of marks obtained by Sundari in first and second papers is 40% and 80% respectively.

Percentage of marks obtained by Kusu in first and second papers is 50% and 90%, respectively.

Percentage of marks obtained by Jyoti in first and second papers is 30% and 90% respectively.

From the above, we see that Jyoti's progress is maximum.

Answer: (a)

Let the no. be 10x + y

then y = x + 2 or y – x = 2 ...... (i)

(10y + x) – (10x + y) = 18

or, 9y – 9x = 18

y – x = 2 ...... (ii)

From eq. (i) and (ii) we can't get any conclusion.

Answer: (d)

Let the two numbers be x and y.

∴ xy = 192, x + y = 28 .................(i)

∴ ${(x – y)}^2 = {(x + y)}^2$ – 4xy = 784 – 768 = 16

∴ x – y = 4 ........(ii)

Combining (i) and (ii), x =16, and y = 12.