algebraic expressions Model Questions & Answers, Practice Test for ibps clerk prelims 2023
ibps clerk prelims 2023 SYLLABUS WISE SUBJECTS MCQs
Ratio & Proportion
Percentages
Profit & Loss
Time & Work
Time & Distance
Simple Interest & Compound Interest
Mensuration: Area & Volumes
Algebraic Expressions
Trigonometric Ratios & Identity
Linear Equations
Quadratic Equations
Logarithm
The product of the ages of Harish and Seema is 240. If twice the age of Seema is more than Harish's age by 4 years, what is Seema's age in years?
Answer: (c)
Let the ages of Harish and Seema be x and y respectively.
According to the question,
x.y = 240 ....... (i)
2y – x = 4 ........(ii)
Solving equations (i) and (ii), we get
y = 12 years
Directions :
In each of the following questions two equations are given. You have to solve them and give answer
- if x > y
- if x < y
- if x = y
- if x ≥ y
- if x ≤ y
I. $x^2$ + 3x + 2 = 0
II. $y^2$ – 4y + 1= 0
Answer: (e)
I. $x^2$ + 3x + 2 = 0
or, (x + 2) (x + 1) = 0
or, x = – 2 or, –1
II. $y^2$ – 4y + 1 = 0 or, y = 2 ± $√3$
Hence, y > x
Free notebooks were distributed equally among children of a class. The number of notebooks each child got was oneeighth of the number of children. Had the number of children been half, each child would have got 16 notebooks. How many notebooks were distributed in all?
Answer: (a)
In case I: Let the no. of children = x.
Hence, total no. of notebooks distributed
$1/8x.x or x^2/8$ .....(i)
In case II: no. of children = $x/2$
Now, the total no. of notebooks
= $16 ×x/2$ ..... (ii)
Comparing (i) & (ii), we get
$x^2/8=8x$
or, x = 64
Hence, total no. of notebooks
= ${64×64}/8=512$
If the numerator of a fraction is increased by 2 and denominator is increased by 3, the fraction becomes 7/9; and if numerator as well as denominator are decreased by 1 the fraction becomes 4/5. What is the original fraction?
Answer: (d)
Let the numerator and denominator be x and y respectively.
Then ${x+2}/{y+3}=7/9$
or, 9 (x + 2) = 7 (y + 3)
or 9x – 7y = 3 ...... (i)
${x-1}/{y-1}=4/5$
⇒ 5x – 4y = 1 ...... (ii)
Solving (i) and (ii), we get
x = 5, y = 6
Reqd fraction = $5/6$
If 3x – 5y = 5 and $x/{x + y}=5/7$then what is the value of x – y?
Answer: (a)
3x – 5y = 5 ...(i)
And $x/{x+y}=5/7$⇒7x = 5x + 5y
⇒2x = 5y ... (ii)
From (i) and (ii), x = 5 and y = 2
∴ x – y = 3
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