puzzles test Model Questions & Answers, Practice Test for ibps clerk mains

Answer: (b)

The number inside the circle is obtained by multiplying the sum of upper number, the lower number and the number corresponding to the position of the letter in English alphabet, by the number on the right and then subtracting the number on the left from the product.

Thus, we have (2 + C + 5) × 3 – 4 = (2 + 3 + 5) × 3 – 4 = 26;

(4 + 4 + 4) × 5 – 10 = (4 + 8 + 4) × 5 – 10 = – 70

∴ (8 + J + 6) × ? – 6 = 90

⇒ (8 + 10 + 6) × ? = 96

⇒ ? = ${96}/{24}$ = 4

Answer: (c)

32 + 11 + 58 = 101

13 + 71 + 17 = 101

37 + ? + 25 = 101

∴ ? = 101 – 37 – 25 = 39

Answer: (b)

The arrangement is as follows :

In fig. (A), (3²+ 6² ) – (2² + 4² ) = (9 + 36) – (4 + 16)

= 45 – 20 = 25

In fig. (B), (7² + 11² ) – (8² + 6² ) = (49 + 121) – (64 + 36)

= 170 – 100 = 70

In fig. (C), let the missing number be x.

Then, (1² + 4²) – (5² + x²) = –12

or 17 + 12 = (5² + x²) or x² = 29 – 25 = 4

or x = 2

Answer: (a)

In fig. (A), (16 – 6)² + (5 – 2)² = 10² + 3² = 109.

In fig. (B), (22 – 15)² + (21 – 19)² = 7²+ 2² = 53.

∴ In fig. (C), missing number

= (17 – 13)² + (51 – 48)² = 4² + 3² = 25.

Answer: (a)

In the first row, $6 × 3/2 = 9, 6 × 5/2 = 15$

In the second row, $8 × 3/2 = 12, 8 × 5/2 = 20$

∴ In the third row, missing number $4 × 5/2$