set 2 MCQ Questions & Answers Detailed Explanation
MOST IMPORTANT general science mcq - 5 EXERCISES
The following question based on mechanics (mass, force, acceleration, work, energy, momentum, velocity) topic of general science mcq
(a) zero
(b) negative
(c) positive
(d) undefined
The correct answers to the above question in:
Answer: (a)
Practice mechanics (mass, force, acceleration, work, energy, momentum, velocity) (set 2) Online Quiz
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Read more mechanics work and energy Based General Science Questions and Answers
Question : 1
In case of negative work the angle between the force and displacement is
a) 90°
b) 45°
c) 0°
d) 180°
Answer »Answer: (d)
Question : 2
The circular motion of a particle with constant speed is
a) periodic and simple harmonic
b) periodic but not simple harmonic
c) simple harmonic but not periodic
d) neither periodic nor simple harmonic
Answer »Answer: (b)
In the circular motion of a particle with constant speed, the particle repeats its motion after a regular interval of time but does not oscillate about a fixed point.
So, the motion of particles is periodic but not simple harmonic.
Question : 3
The potential energy is always the same for an object with the same
a) Acceleration
b) Speed
c) Velocity
d) Position
Answer »Answer: (d)
Question : 4
A man waves his arms while walking. This is to
a) increase the velocity
b) ease the tension
c) keep constant velocity
d) balance the effect of earth’s gravity
Answer »Answer: (d)
Question : 5
A passenger in a moving train tosses a coin. If the coin falls behind him, the train must be moving with
a) a uniform speed
b) a deceleration
c) an acceleration
d) any of the above
Answer »Answer: (c)
Question : 6
A balloon filled with CO2 released on earth would (neglect viscosity of air)
a) fall with a constant acceleration 3.4 m/s2
b) fall with an acceleration 9.8 m/s2
c) climb with an acceleration 9.8 m/s2
d) fall with acceleration and then would attain a constant velocity
Answer »Answer: (a)
If B is upthrust of air on balloon, and a is downward acceleration, then
Mg – B = Ma
⇒ a = ${Mg - B}/M = g- {{Vρ}_{air}g}/{{Vρ}_{CO_2}}$
=$(1-{{Vρ}_{air}}/{{Vρ}_{CO_2}})g = (1-{28.8}/{44})×9.8m/{s}^2$
=3.4m/${s}^2$
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