Practice Find angle between hands clock - verbal reasoning Online Quiz (set-1) For All Competitive Exams
Q-1) What will be the angle between the hands of clock at 8 : 30?
(a)
(b)
(c)
(d)
∴ Angle traced by hour hand per minute = $(1/2)^o$
∴ Angled traced by hour hand in 8 h 30 min =$[{(8 × 60) + 30}x1/2]^o$
= $[{480 + 30} ×1/2]° = 510 × (1/2)^o = 255°$
Then, Angle traced by minute hand per minute = 6°
∴ Angle traced by minute hand in 30 min = 30 × 6° = 180°
Hence, Required angle = (255° - 180°) = 75°
Q-2) Find the angle between the hands of clock at 8 : 20.
(a)
(b)
(c)
(d)
∴ Angle traced by hour hand per minute =$(1/2)^o$
∴Angle traced by hour hand in 8h 20 min = ( 8 x 60 + 20) ×$ 1/2$ = 205°
Again, angle traced by minute hand per minute = 6°
∴ again traced by minute hand in 20 min = 20 × 6°
= 120°
Therefore required angle = (250° - 120°) = 130°
Q-3) What will be the angle between the hands of clock at 7 : 10?
(a)
(b)
(c)
(d)
∴ angle traced by hour hand per minute = $(1/2)^o$
∴ angled traced by hour hand in 8 h 30 min =$[{(8 × 60) + 30}x1/2]^o$
= $[{480 + 30} ×1/2]^o$ = 510 × $(1/2)^o$ = 255°
∴ Angle traced by minute hand per minute = 6°
∴ Angle traced by minute hand in 30 min = 30 × 6° = 180°
∴ required angle = (255° - 180°) = 75°
Q-4) Find the angle traced by hour hand of a correct clock between 8 O' clock and 2O' clock.
(a)
(b)
(c)
(d)
∴ Angle traced by hour hand per minute = $(1/2)^o$
∴ Angle traced by hour hand in 1 h = 1°/2 × 60 = 30°
Time period between 8 O' clock to 2 O' clock = 6h
∴ angle traced by hour hand in 6h = 30° × 6 = 180°
Q-5) What angle will be traced by the hands of a clock at 7 : 35?
(a)
(b)
(c)
(d)
Angle traced by hour hand per minute = $(1/2)^o$
∴ Angle traced by hour hand in 7 h 35 min = [(7 × 60) + 35] × $1°/2$
= (420 + 35) × 1°/2 = 455 × $1°/2$ = 227 $1°/2$
∴ angle traced by minute hand per minute = 6°
Angle traced by minute hand in 35 min = 35 × 6° = 210°
∴ required angle = 227 1°/2 - 201° = 17$1°/2$
Q-6) The angle between the minute hand and the hour hand of a clock when the time is 4:20, is
(a)
(b)
(c)
(d)
Angle traced by hour hand in $13/3 hrs = (360/12 × 13/3)^o= 130°$
Angle traced by min. hand in $20 min = (360/60 × 20)^o = 120°$
∴ Required angle = (130° - 120°) = 10°
Q-7) What will be the angle between the hands of clock at 9 : 30?
(a)
(b)
(c)
(d)
∴ Angle traced by hour hand per minute = $(1/2)^o$
∴ Angle traced by hour hand in 9 h 30 min
= [(9 × 60) + 30] × $1°/2$ = 570 × $1°/2$ = 285°
∴ angle traced by minute hand per minute = 6°
∴ angle traced by minute hand in 30 min = 30 × 6° = 180°
∴ required angle = (285° - 180°) = 105°
Q-8) Find the angle between the two hands of clock at 4 : 10.
(a)
(b)
(c)
(d)
∴ angle traced by hour hand per minute = $(1/2)^o$
Therefore angle traced by hour hand in 4 h 10 min = $[(4 × 60) + 10] × 1°/2 = 250 × 1°/2 = 125°$
∴ angle traced by minute hand per minute = 6°
∴ angle traced by minute hand in 10 min = 10 × 6° = 60°
∴ required angle = 125° - 60° = 65°
Q-9) Through what angle does the minute hand of a clock turn in 5 minutes?
(a)
(b)
(c)
(d)
Angle traced by the minute hand in 5 minutes = $(360/60 × 5)^o = 30°$
Q-10) A clock gains 5 minutes in one hour. Therefore, the angle traversed by the minute hand in 1 hour is
(a)
(b)
(c)
(d)
Clearly, the minute hand traverses 65 minutes in 1 hour.
∴ Required angle = $(360/60 × 65)^o = 360°$