Practice Basic calendar problems - verbal reasoning Online Quiz (set-1) For All Competitive Exams
Q-1) How many Monday's are there in a particular month of a particular year if the month ends on Wednesday?
(a)
(b)
(c)
(d)
There are months of 30, 31 and 28 days and last day of the month are Wednesday.
So, using 28 and 30 days, there are 4 Mondays.
Using 31 days, there are 5 Mondays
So, it cannot be specified.
Q-2) How many days are there in x weeks x days?
(a)
(b)
(c)
(d)
Q-3) Which of the following is not a leap year?
(a)
(b)
(c)
(d)
Q-4) Which of the following is a leap year?
(a)
(b)
(c)
(d)
(e)
The century year which is completely divisible by 400, is a leap year.
Thus, the year 2800 is a leap year.
Q-5) The calendar for the year 2007 will be the same for the year:
(a)
(b)
(c)
(d)
Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd days.
Sum = 14 odd days = 0 odd day.
Therefore, Calendar for the year 2018 will be the same as for the year 2007.
Q-6) The year next to 1990 will have the same calendar as that of the year 1990.
(a)
(b)
(c)
(d)
The year 1990 has 365 days. i.e. 1 odd day,
the year 1991 has 365 days, i.e. 1 odd day,
the year 1992 has 366 days i.e. 2 odd days.
The likewise year 1993, 1994, 1995 have 1 odd day each.
The sum of odd days, so calculated from years 1990 - 95
= (1 + 1 + 2 + 1 + 1 + 1) = 7 days = 0 odd day
Hence, the year 1996 will have the same calendar as that of the year 1990.
Q-7) The last day of a century cannot be
(a)
(b)
(c)
(d)
Q-8) For a certain month, the dates of three of the Sundays are even numbers. Then, the 15th of that month falls on a
(a)
(b)
(c)
(d)
The dates of three of the Sundays are even number is 2, 9, 16, 23, 30.
So, on 16th of that month = Sunday,
15th of that month falls on a Saturday.
Q-9) The day on 18.09.1977 was Sunday A couple was married on this date. How many marriage anniversaries would fall on Sunday in the next 15 yr?
(a)
(b)
(c)
(d)
1977 is an ordinary year.
We know that the calendar of an ordinary year repeats after 6 yrs or 11 yrs.
Let us check for the number of odd days in 6th and 11th years.
| Year | Number of odd days |
| 1978 | 1 |
| 1979 | 1 |
| 1980 | 2 |
| 1981 | 1 |
| 1982 | 1 |
| 1983 | 1 |
| 1984 | 2 |
| 1985 | 1 |
| 1986 | 1 |
| 1987 | 1 |
| 1988 | 2 |
From the above table, Number of odd days from 18.09.1977 to 18.09.1983 = 7,
i.e., 0 odd days
It means that in 1983, 18th September would fall on Sunday.
From the above table, a number of odd days from 18.09.1977 to 18.09.1988 = 14
i.e., 0 odd days.
Now, it is clear that 2 marriage anniversaries would fall on Sunday in the next 15 yr.
Q-10) In a month of 31 days, third Thursday falls on 16th, then what will be the last day of the month?
(a)
(b)
(c)
(d)
(e)
Number of days left in the month after 16th = 31 - 16 = 15
Number of odd days = 15/7 = 2 weeks + 1 odd day
Therefore, Required day = Thursday + 1 odd day = Friday
As, 16th of the month is third Thursday, the day which is two weeks after this day is fifth Thursday.
So, one day after 5th Thursday is 5th Friday.