Practice Based on cricket exam - quantitative aptitude Online Quiz (set-1) For All Competitive Exams

Q-1)   A batsman in his 12th innings makes a score of 120, and thereby increases his average by 5. The average score after 12th innings is

(a)

(b)

(c)

(d)

Explanation:

Average runs after 12 innings = x (let)

Average runs after 11 innings = x – 5

According to the question,

12x = (x – 5) × 11 + 120

⇒ 12x – 11x = 120 – 55

⇒ x = 65


Q-2)   The batting average for 30 innings of a cricket player is 40 runs. His highest score exceeds his lowest score by 100 runs. If these two innings are not included, the average of the remaining 28 innings is 38 runs. The lowest score of the player is :

(a)

(b)

(c)

(d)

Explanation:

Lowest score = x

Highest score = x + 100

∴ 28 × 38 + x + x + 100 = 30 × 40

⇒ 1064 + 2x + 100 = 1200

⇒ 2x = 1200 – 1164 = 36

⇒ x = 18


Q-3)   Sachin Tendulkar has a certain average for 11 innings. In the 12th innings he scores 120 runs and thereby increases his average by 5 runs. His new average is

(a)

(b)

(c)

(d)

Explanation:

Sachin’s new average = x runs

Total runs in 11 innings = 11 (x – 5)

∴ 11 (x – 5) + 120 = 12x

∴ 12x – 11x = 65

∴ x = 65 runs


Q-4)   A cricketer has a mean score of 60 runs in 10 innings. Find out how many runs are to be scored in the eleventh innings to raise the mean score to 62?

(a)

(b)

(c)

(d)

Explanation:

Required runs = 60 + 11 × 2 = 82 runs

Aliter : Using Rule 18,

If in the group of N persons, a new person comes at the place of a person of 'T’ years, so that average age,

increases by 't’ years

Then, the age of the new person = T + N.t.

Here, T = 60, N = (10 + 1) t = 62 – 60 = 2

Required Runs = T + Nt

= 60 + 11 × 2 = 82


Q-5)   A cricketer has a certain average of runs for his 8 innings. In the ninth innings, he scores 100 runs, thereby increases his average by 9 runs. His new average of runs is

(a)

(b)

(c)

(d)

Explanation:

Let the average of runs of the cricketer in 8 innings be x .

According to the question,

${8x+100}/9$=x+9

⇒ 8x + 100 = 9x + 81

⇒ x = 100 – 81 = 19

∴ New average of runs = 19 + 9 = 28


Q-6)   A batsman makes a score of 87 runs in the 17th innings and thus increased his average by 3. Find his average after 17th innings.

(a)

(b)

(c)

(d)

Explanation:

Average runs in 16 innings = 87 – 17 × 3 = 87 – 51 = 36

∴ Required average = 36 + 3 = 39 runs


Q-7)   A cricketer whose bowling average is 12.4 runs per wicket, takes 5 wickets for 26 runs and thereby decreases his average by 0.4. The number of wickets taken by him till the last match was

(a)

(b)

(c)

(d)

Explanation:

Required number of wickets = x (let)

According to question,

12.4 × x + 26 = (x + 5) (12.4 – 0.4) = (x + 5) × 12

⇒ 12.4x + 26 = 12x + 60

⇒ 12.4x – 12x = 60 – 26

⇒ 0.4x = 34

⇒ x = $34/{0.4}$ = $340/4$ = 85


Q-8)   The averages of runs scored by a cricket player in 11 innings is 63 and the average of his first six innings is 60 and the average of last six innings is 65. Find the runs scored by him in the sixth innings.

(a)

(b)

(c)

(d)

Explanation:

Runs scored by the cricketer in the 6th innings

= 6 × 60 + 6 × 65 – 11 × 63

= 360 + 390 – 693 = 57


Q-9)   A batsman in his 12th innings makes a score of 63 runs and there by increases his average scores by 2. What is his average after the 12th innings?

(a)

(b)

(c)

(d)

Explanation:

Extra runs = 12 × 2 = 24

∴ Required average = 63 – 24 = 39


Q-10)   The average of runs scored by a cricketer in his 99 innings is 99. How many runs will he have to score in his 100th innings so that his average of runs in 100 innings may be 100?

(a)

(b)

(c)

(d)

Explanation:

Number of runs scored in 100th innings

= 100 × 100 – 99 × 99

= 10000 – 9801 = 199

OR

Increase in average = 1 run

∴ Runs scored in 100th innings = 100 + 99 = 199