model 4 finding unit place of a number Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 6 EXERCISES

Top 10,000+ Aptitude Memory Based Exercises

The following question based on number system topic of quantitative aptitude

Questions : Unit digit in $(264)^102 + (264)^103$ is :

(a) 8

(b) 0

(c) 6

(d) 4

The correct answers to the above question in:

Answer: (b)

Unit digit in $(264)^4$ i.e. 4 × 4 × 4 × 4 is 6

Unit digit in $(264)^100$ is also 6.

Now, $(264)^102 = (264)^100 × (264)^2$

= (Unit digit 6) × (Unit digit 6)=36

∴ Unit digit is 6

Similarly,

$(264)^103 + (264)^100 × (264)^3$

= (Unit digit 6) × (Unit digit 4)=24

∴ Unit digit is 4

Therefore, the unit digit in $(264)^102 + (264)^103$ is

6 + 4 = 10 i.e. 0.

Practice number system (model 4 finding unit place of a number) Online Quiz

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Read more unit place Based Quantitative Aptitude Questions and Answers

Question : 1

The digit in unit’s place of the product $(2153)^167$ is :

a) 9

b) 1

c) 7

d) 3

Answer: (c)

Unit’s digit in $3^4$ = 1

So, unit digit in $3^164$ = 1

Now, unit's digit in $(2153)^167$ = unit digit in $3^167$

= unit digit in $3^3$ = 7

Question : 2

The unit’s digit in the product $7^71 × 6^63 × 3^65$ is

a) 4

b) 1

c) 3

d) 2

Answer: (a)

$7^1 = 7, 7^2 = 49, 7^3 = 343, 7^4 = 2401$

$3^1 = 3; 3^2 = 9; 3^3 = 27; 3^4 = 81;$

i.e. the digit at unit’s place gets repeated after power 4. Unit 6 remains same for any power.

∴ Required unit’s digit = Unit’s digit in the product of $7^3 × 6 × 3^1$ = 4

Question : 3

What will be the unit digit in the product $7^105$ ?

a) 1

b) 5

c) 9

d) 7

Answer: (d)

$7^1 = 7$, $7^2 = 9$, $7^3 = 3$, $7^4 = 1$

$7^5 = 7$, $7^6 = 9$, $7^7 = 3$, ... $7^104 = 1$

ie, $105/4$ = [R(1)]

ie, $7^105$= 7

Question : 4

Find the unit digit in the product $(4387)^245 × (621)^72$ .

a) 7

b) 1

c) 5

d) 2

Answer: (a)

$7^1 = 7, 7^2 = 49, 7^3 = 343, 7^4 = 2401, 7^5$ = 16807

i.e. The unit’s digit repeats itself after power 4.

Remainder after we divide 245 by 4 = 1

Unit’s digit in the product of $(4387)^245 × (621)^72$ = Unit’s digit in the product of $(4387)^1 × (621)^72$ = 7 × 1 = 7

Question : 5

The unit digit in the sum of $(124)^372 + (124)^373$ is

a) 0

b) 5

c) 2

d) 4

Answer: (a)

$4^1 = 4, 4^2 = 16, 4^3 = 64, 4^4 = 256, 4^5 = 1024$

Remainder on dividing 372 by 4 = 0

Remainder on dividing 373 by 4 = 1

Required unit digit = Unit digit of the sum of 6 + 4 = 0

Question : 6

The digit in unit’s place of the number $(1570)^2 + (1571)^2 + (1572)^2 + (1573)^2$ is :

a) 3

b) 4

c) 2

d) 1

Answer: (b)

Unit's digit in $(1570)^2$ = 0

Unit's digit in $(1571)^2$ = 1

Unit's digit in $(1572)^2$ = 4

Unit's digit in $(1573)^2$ = 9

∴ Required unit’s digit = Unit’s digit (0 +1+4 + 9) = 4

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