model 5 simplifying roots of roots Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 5 EXERCISES
The following question based on power, indices and surds topic of quantitative aptitude
(a) lies between 1 and 2
(b) lies between 0 and 1
(c) is greater than 2
(d) equals 1
The correct answers to the above question in:
Answer: (a)
Let x = $√{1+√{1+√{1 +...}}}$
On squaring both sides
$x^2 =1+√{1+√{1+√{1 +...}}}$
$x^2$ = 1 + x
$x^2$ - x - 1 = 0
$x = {+1± √{1+4}}/2 = {+1 ±√ 5}/2$
But sum of + ve numbers can't be negative.
$x={1+ √5}/2 ={1+ 2.236}/2$
= ${3.236}/2 =1.618$
Thus 1 < 1.618 < 2
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Read more simplifying roots of roots Based Quantitative Aptitude Questions and Answers
Question : 1
$√{12+√{12+√{12 +...}}}$ is equal to
a) 6
b) 4
c) 2
d) 3
Answer »Answer: (b)
Let x = $√{12+√{12+√{12 +...}}}$
On squaring both sides,
$x^2 =12+√{12+√{12+√{12 +...}}}$
$x^2$ = 12 + x
$x^2$ - x - 12 = 0
$x^2$ - 4x + 3x - 12 = 0
x (x - 4) + 3 (x - 4) = 0
(x - 4) (x + 3) = 0
x = 4, - 3
The given expression is positive.
x = 4
Using Rule 25If $√{x+√{x+√{x +...∞}}}$ where, x=n(n + 1)then $√{x+√{x+√{x +...∞}}}$ = (n + 1)
$√{12+√{12+√{12}}}$=4
It is because
12 = 3 × 4 = n (n + 1)
Question : 2
The value of the following is : $√{12+√{12+√{12 +...}}}$
a) 2
b) $2√3$
c) 4
d) $2√2$
Answer »Answer: (c)
x = $√{12+√{12+√{12 +...}}}$
On squaring both sides,
$x^2 = 12 + √{12+√{12+√{12 +...}}}$
$x^2$ = 12 + x
$x^2$ - x - 12 = 0
$x^2$ - 4x + 3x - 12 = 0
x (x - 4) + 3 (x - 4) = 0
(x - 4) (x + 3) = 0
x = 4 because x ≠ - 3
Question : 3
${√{10+√{ 25+√{ 108+√{ 154+√{ 225}}}}}}/√^3{8}$= ?
a) 8
b) 2
c) $1/2$
d) 4
Answer »Answer: (b)
${√{10+√{ 25+√{ 108+√{ 154+√{ 225}}}}}}/√^3{8}$= ?
?=${√{10+√{ 25+√{ 108+√{ 154+15}}}}}/√^3{2×2×2}$
=${√{10+√{ 25+√{ 108+√{169}}}}}/2$
=${√{10+√{ 25+√{ 108+13}}}}/2$
=${√{10+√{ 25+√{121}}}}/2$
=${√{10+√{ 25+11}}}/2$
=${√{10+√{36}}}/2={√{10+6}}/2$
=${√{16}}/2=4/2=2$
Question : 4
$√{6+√{6+√{6 +...}}}$ is equal to
a) 5
b) 4
c) 6
d) 3
Answer »Answer: (d)
Let x = $√{6+√{6+√{6 +...}}}$
Squaring on both sides,
$x^2 = 6+√{6+√{6+√{6 +...}}}$
$x^2$ = 6 + x
$x^2$ - x - 6 = 0
$x^2$ - 3x + 2x - 6 = 0
x (x - 3) + 2 (x - 3) = 0
(x + 2) (x - 3) = 0
x = 3 because x ≠ - 2
$√{6+√{6+√{6 +...}}}$ = 3
It is because
6 = 2 × 3 = n (n + 1)
Question : 5
Find the value of $√{10+√{ 25+√{ 108+√{ 154+√{ 225}}}}}$.
a) 8
b) 10
c) 4
d) 6
Answer »Answer: (c)
Expression
=$√{10+√{ 25+√{ 108+√{ 154+√{ 225}}}}}$
=$√{10+√{ 25+√{ 108+√{ 154+15}}}}$
=$√{10+√{ 25+√{ 108+√{169}}}}$
=$√{10+√{ 25+√{ 108+13}}}$
=$√{10+√{ 25+√{121}}}$
=$√{10+√{ 25+11}}$
=$√{10+6}=√16=4$
Question : 6
$√{3√{3√{3...}}}$ is equal to
a) $2√3$
b) 3
c) $3√3$
d) $√3$
Answer »Answer: (b)
Let x = $√{3√{3√{3...}}}$
Squaring both sides,
$x^2 = 3√{3√{3√{3...}}}$ = 3x
$x^2$ - 3x = 0
x (x - 3) = 0
x = 3 because x ≠ 0
Using Rule 23$√{x√{x√{x...n times}}}= x^(1-1/{x^n})$
$√{3+√{3+√{3+...∞}}}$ = 3
It is because, here
n = ∞ and x =3
$√{3+√{3+√{3+...∞}}}=3^(1-1/{3∞})$
= $3^(1 - 0)$ [${something}/∞ = 0$] = 3
GET power, indices and surds PRACTICE TEST EXERCISES
model 1 find largest and smallest value
model 2 based on simplification
model 3 based on positive and negative exponent
model 4 simplifying roots with values
model 5 simplifying roots of roots
power, indices and surds Shortcuts and Techniques with Examples
-
model 1 find largest and smallest value
Defination & Shortcuts … -
model 2 based on simplification
Defination & Shortcuts … -
model 3 based on positive and negative exponent
Defination & Shortcuts … -
model 4 simplifying roots with values
Defination & Shortcuts … -
model 5 simplifying roots of roots
Defination & Shortcuts …
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