model 1 basic average questions Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 9 EXERCISES
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Basic Average Questions Practice Test, Shortcuts, Tricks, PDF »
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New Average Aptitude MCQ Average of Consecutive Numbers »
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Top 99+ Average Aptitude: Twice, One Third of Numbers MCQ »
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New +99 Average Aptitude MCQ Find nth Average of Numbers »
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99+ Average Aptitude Find New Average from Error MCQ Test »
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Top 99+ Aptitude MCQ Test on Average With Excluded Number »
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Top 99+ Aptitude Average on Ages & Weights MCQ Test Quiz »
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Top Aptitude Average MCQ Find Monthly Income for Average »
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Top 149+ Aptitude Average on Cricket & Exam MCQ Test Quiz »
The following question based on average topic of quantitative aptitude
(a) increase by 2
(b) remain the same
(c) increase by 1.5
(d) increase by 1
The correct answers to the above question in:
Answer: (d)
Given,
$\text"(a + a + 1 + a + 2 + a + 3 + a + 4 + a + 5 + a + 6 + a + 7 + a + 8)"/9 = n$
$=> \text"(9a + 36)"/9 = n$
=> a + 4 = n -------------------- ( 1 )
If the next 2 numbers are included , let new average = k
$\text"(a + a + 1 + a + 2 + a + 3 + a + 4 + a + 5 + a + 6 + a + 7 + a + 8 + a + 9 + a + 10)"/11 = k$
$\text"(11a + 55)"/11 = k$
a + 5 = k -------------------- ( 2 )
Subtracting ( 1 ) from ( 2 ) , we get :
a + 5 - a - 4 = k - n
=> k - n = 1
=> k = n + 1
Therefore the new average is n + 1
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Read more simple average Based Quantitative Aptitude Questions and Answers
Question : 1
The average of 5 consecutive integers starting with ‘m’ is n. What is the average of 6 consecutive integers starting with (m + 2) ?
a) $\text"2n+5"/2$
b) $n+2$
c) $n+3$
d) $\text"2n+9"/2$
Answer »Answer: (a)
According to the question let m = 1
∴ 5 consecutive integers are = 1,2,3,4,5
$\text"1+2+3+4+5"/5=n$
$n = 15/5=3$
6 consecutive integers starting with (m + 2) are = 3,4,5,6,7,8
∴$\text"3+4+5+6+7+8"/6=33/6=11/2$
Now check from option to put n = 3
While in Option :(a) $\text"2n+5"/2 = 11/2 $
Question : 2
If a, b, c, d, e are five consecutive odd numbers, their average is
a) $5(a+4)$
b) $\text"abcde"/5$
c) $5(a+b+c+d+e)$
d) $a+4$
Answer »Answer: (d)
Question : 3
The average monthly income (in ₨) of certain agricultural workers is S and that of other workers is T. The number of agricultural workers is 11 times that of other workers. Then, the average monthly income (in ₨) of all the workers is :
a) $\text"S+11T"/12$
b) $\text"S+T"/12$
c) $\text"11S+T"/12$
d) $1/\text"11S"+T$
Answer »Answer: (c)
Question : 4
a, b, c, d, e, f, g are consecutive even numbers. j, k, l, m, n are consecutive odd numbers. The average of all the numbers is
a) $3(\text"a+n"/2)$
b) $(\text"l+d"/2)$
c) $\text"a+b+m+n"/4$
d) $\text"j+c+n+g"/4$
Answer »Answer: (b)
According to the question consecutive even numbers = a, b, c, d, e, f, g
Consecutive odd numbers = j, k, l, m, n
Consecutive even number = 2, 4, 6, 8, 10, 12, 14
$\text"2+4+6+8+10+12+14"/7=56/7=8$ middle term
Consecutive odd numbers 1, 3, 5, 7, 9
$\text"1+3+5+7+9"/5=25/5$ middle term
Same as in the above situation.
Average of a, b, c, d, e, f, g = d
Average of j, k, l, m, n, = l
∴ Required average = ${d+l}/2$
Question : 5
Average of n numbers is a. The first number is increased by 2, second one is increased by 4, the third one is increased by 8 and so on. The average of the new numbers is
a) $a+(2^(n-1)-1)/n$
b) $a+2(2^n-1)/n$
c) $a+2^(n-1)/n$
d) $a+(2^n-1)/n$
Answer »Answer: (b)
Sum of new numbers
= na + (2 + 4 + 8 + 16 ..... to n terms)
Now, S = 2 + 4 + 8 + 16 + ..... to n terms
Here, a = first term = 2
r = common ratio = $4/2$ = 2
It is a geometric series.
∴ S =${a({r^n} - 1)}/{r-1}$= ${2({2^n} - 1)}/{2-1}$
= 2 ($2^n$ –1)
∴ Required average
= ${na +2({2^n}-1)}/n$
a +${2({2^n}-1)}/n$
Question : 6
In a class, average height of all students is ‘a’ cms. Among them, average height of 10 students is ‘b’ cms and the average height of the remaining students is ‘c’ cms. Find the number of students in the class. (Here a > c and b > c )
a) $(a(b-c))/(a-c)$
b) $(b-c)/(a-c)$
c) $(b-c)/\text"10(a-c)"$
d) $\text"10(b-c)"/(a-c)$
Answer »Answer: (d)
Let the total number of students in the class be n.
According to the question,
an = 10 × b + (n – 10) c
⇒ an = 10b + nc – 10c
⇒ an – cn = 10b – 10c
⇒ n (a – c) = 10 (b – c)
$⇒ n =\text"10 (b - c )"/ ( a - c )$
GET average PRACTICE TEST EXERCISES
model 1 basic average questions
model 2 average of consecutive numbers
model 3 twice, thrice, one third etc. of numbers
model 4 find nth average from 1st & last number
model 5 find new average from error
model 6 find average of excluded number
model 7 average on ages/weight
model 8 find monthly income
model 9 average on cricket/exam
average Shortcuts and Techniques with Examples
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model 1 basic average questions
Defination & Shortcuts … -
model 2 average of consecutive numbers
Defination & Shortcuts … -
model 3 twice, thrice, one third etc. of numbers
Defination & Shortcuts … -
model 4 find nth average from 1st & last number
Defination & Shortcuts … -
model 5 find new average from error
Defination & Shortcuts … -
model 6 find average of excluded number
Defination & Shortcuts … -
model 7 average on ages/weight
Defination & Shortcuts … -
model 8 find monthly income
Defination & Shortcuts … -
model 9 average on cricket/exam
Defination & Shortcuts …
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