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MOST IMPORTANT quantitative aptitude - 9 EXERCISES

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The following question based on average topic of quantitative aptitude

Questions : A librarian purchased 50 story– books for his library. But he saw that he could get14 more books by spending Rs. 76 more and the average price per book would be reduced by Re. 1. The average price (in Rs.) of each book he bought, was :

(a) 25

(b) 20

(c) 10

(d) 15

The correct answers to the above question in:

Answer: (c)

Let the average cost of each book bought (of 64 books) be Rs.x.

According to the question,

64 × x – 50(x + 1) = 76

⇒ 64x – 50x – 50 = 76

⇒ 14x = 76 + 50 = 126

⇒ x = $126/14$ = 9

∴ Required average price

= 9 + 1 = Rs. 10

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Read more simple average Based Quantitative Aptitude Questions and Answers

Question : 1

Total weekly emoluments of the workers of a factory is Rs.1534. Average weekly emolument of a worker is Rs.118. The number of workers in the factory is :

a) 13

b) 12

c) 14

d) 16

Answer: (a)

Using Rule 1,

Average of two or more numbers/quantities is called the mean of these numbers, which is given by

$\text"Average(A)" = \text"Sumof observation / quantities"/\text"No of observation / quantities"$

∴ S = A × n

Number of workers in the factory = $1534/118$ = 13

Question : 2

The average weight of first 11 persons among 12 persons is 95 kg. The weight of 12th person is 33 kg more than the average weight of all the 12 persons. The weight of the 12th person is

a) 131 kg

b) 97.45 kg

c) 128 kg

d) 128.75 kg

Answer: (a)

Weight of 12th person = x kg (let).

∴ Average weight of 12 persons

= $({11×95+x}/12)$kg

According to the question,

${11×95+x}/12$ +33 = x

⇒ 1045 + x + 396 = 12x

⇒ 1441 = 11x

⇒ x = $1441/11$ = 131 kg.

Question : 3

The average of x numbers is $y^2$ and the average of y numbers is $x^2$ . So the average of all the numbers taken together is

a) ${x^2 + y^2}/{x + y}$

b) x$y^2$ + y$x^2$

c) xy

d) ${x^3 + y^3}/{x + y}$

Answer: (c)

Total sum of x numbers = x$y^2$

Total sum of y numbers = y$x^2$

∴ Required average

= ${xy^2+yx^2}/{x+y}$

=${xy(y+x)}/{x+y}$ = xy

Aliter : Using Rule 10,

Here, $n_1$ = x, $a_1$ = $y^2$

$n_2$ = y, $a_2$ = $x^2$

∴ Average = ${n_1a_1+n_2a_2}/{n_1+n_2}$

= ${xy^2+yx^2}/{x+y}$

= xy$({x+y}/{x+y})$ = xy

Question : 4

The average marks obtained by a class of 60 students is 65. The average marks of half of the students is found to be 85. The average marks of the remaining students is

a) 55

b) 65

c) 45

d) 35

Answer: (c)

Let average marks of remaining 30 students be x.

∴ 65 = ${30×85+30×x}/60$

⇒ 65 × 60 = 2550 + 30x

⇒ 3900 = 2550 + 30x

⇒ 30x = 3900 – 2550 = 1350

⇒ x = $1350/30$ = 45.

Question : 5

The average monthly salary of all the employees in an industry is Rs.12,000. The average salary of male employees is Rs.15,000 and that of female employees is Rs.8,000. What is the ratio of male employees to female employees ?

a) 4 : 3

b) 2 : 5

c) 3 : 4

d) 5 : 2

Answer: (a)

Male employees = x

Female employees = y

∴ (x + y) 12000 = x × 15000 + y × 8000

⇒ (x + y) × 12 = 15x + 8y

⇒ 12x + 12y = 15x + 8y

⇒ 3x = 4y

⇒ $x/y$ = $4/3$ ⇒ x : y = 4 : 3

Question : 6

If the average weight of 6 students is 50 kg; that of 2 students is 51 kg; and that of other 2 students is 55 kg; then the average weight of all students is

a) 52 kg

b) 51.2 kg

c) 51.5 kg

d) 61 kg

Answer: (b)

Using Rule 10,

If the average of '$n_1$' numbers is $a_1$ and the average of '$n_2$' numbers is $a_2$, then average of total numbers $n_1$ and $n_2$ is

$Average = {n_1a_1 + n_2a_2}/{n_1 + n_2}$

Required average weight

$(50×6+51×2+55×2)/10$

= ${300+102+110}/10$ = $512/10$

= 51.2 kg

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