model 1 basic average questions Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 9 EXERCISES

Top 10,000+ Aptitude Memory Based Exercises

The following question based on average topic of quantitative aptitude

Questions : The average of 100 observations was calculated as 35. It was found later, that one of the observations was misread as 83 instead of 53. The correct average is :

(a) 35.7

(b) 36.7

(c) 34.7

(d) 32.7

The correct answers to the above question in:

Answer: (c)

Difference = 83 – 53 = 30

Incorrect observation > Correct observation

∴ Required average

= 35 - $30/100$ = 35 – 0.3 = 34.7

Practice average (model 1 basic average questions) Online Quiz

Discuss Form

Valid first name is required.
Please enter a valid email address.
Your genuine comment will be useful for all users! Each and every comment will be uploaded to the question after approval.

Read more simple average Based Quantitative Aptitude Questions and Answers

Question : 1

Three Science classes A, B and C take a Life Science test. The average score of class A is 83. The average score of class B is 76. The average score of class C is 85. The average score of class A and B is 79 and average score of class B and C is 81. Then the average score of classes A, B and C is

a) 80.5

b) 80

c) 81

d) 81.5

Answer: (d)

Using Rule 10,

If the average of '$n_1$' numbers is $a_1$ and the average of '$n_2$' numbers is $a_2$, then average of total numbers $n_1$ and $n_2$ is

$Average = {n_1a_1 + n_2a_2}/{n_1 + n_2}$

Students in class A ⇒ x

Students in class B ⇒ y

Students in class C ⇒ z

For classes A and B,

${83x + 76y}/{x+y}$ = 79

⇒ 83x + 76y = 79x + 79y

⇒ 83x – 79x = 79y – 76y

⇒ 4x = 3y

For classes B and C

${76y+85z}/{y+z}$= 81

⇒ 76y + 85z = 81y + 81z

⇒ 5y = 4z

∴ 20x = 15y = 12z

⇒ ${20x}/60$ = ${15y}/60$ = ${12z}/60$

⇒ $x/3$ = $y/4$ = $z/5$

∴ Required average

${83×3+76×4+85×5}/{3+4+5}$

${249+304+425}/12$ = $978/12$

= 81.5

Question : 2

Out of 20 boys, 6 are each of 1 m 15 cm height, 8 are of 1 m 10 cm and rest of 1 m 12 cm. The average height of all of them is

a) 1 m 21 cm

b) 1 m 12 cm

c) 1 m 21.1 cm

d) 1 m 12.1 cm

Answer: (d)

Using Rule 2,

If the given observations (x) are occuring with certain frequency (A) then,

$Average = {A_1x_1+A_2x_2+...............+A_nx_n}/{x_1+x_2+......+x_n}$

where, $A_1, A_2, A_3, .......... A_n$ are frequencies

Average height

= ${6×1.15+8×1.1+6×1.12}/20$

= ${6.9+8.8+6.72}/20$ = ${22.42}/20$

= 1 metre 12.1 cm

Question : 3

A library has an average number of 510 visitors on Sunday and 240 on other days. The average number of visitors per day in a month of 30 days beginning with Sunday is :

a) 300

b) 290

c) 295

d) 285

Answer: (d)

That month will have 5 sundays.

∴ Required average

= ${5×510+25×240}/30$

= ${2550+6000}/30$

= $8550/30$ = 285

Aliter : Using Rule 10,

Here, $n_1$ = 5, $a_1$ = 510

$n_2$ = 25, $a_2$ = 240

Question : 4

A student was asked to find the arithmetic mean of the following 12 numbers : 3, 11, 7, 9, 15, 13, 8, 19, 17, 21, 14 and x He found the mean to be 12. The value of x will be :

a) 17

b) 31

c) 7

d) 3

Answer: (c)

Using Rule 1,

Average of two or more numbers/quantities is called the mean of these numbers, which is given by

$\text"Average(A)" = \text"Sumof observation / quantities"/\text"No of observation / quantities"$

∴ S = A × n

Mean = ${3 +11+ 9+7+15+ 13+ 8 +19 +17 +21 +14+x}/12$

According to question,

${137+x}/12$ = 12

∴ 137 + x = 144

∴ x = 144 – 137 = 7

Question : 5

The average of 30 numbers is 15. The average of the first 18 numbers is 10 and that of the next 11 numbers is 20. The last number is

a) 60

b) 50

c) 52

d) 56

Answer: (b)

Let the last number be x.

According to the question,

18 × 10 + 11 × 20 + x = 30 × 15

⇒ 180 + 220 + x = 450

⇒ 400 +x = 450

⇒ x = 450 – 400 = 50

Question : 6

The average of marks obtained by 100 candidates in a certain examination is 30. If the average marks of passed candidates is 35 and that of the failed candidates is 10, what is the number of candidates who passed the examination?

a) 80

b) 90

c) 70

d) 60

Answer: (a)

Number of successful students in the exam = x

∴ Number of unsuccessful students = 100 – x

According to the question,

30 = ${35x+10(100-x)}/100$

⇒ 3000 = 35x + 1000 – 10x

⇒ 3000 = 25x + 1000

⇒ 25x = 3000 – 1000 = 2000

⇒ x = $2000/25$ = 80

Recently Added Subject & Categories For All Competitive Exams

New 100+ Compound Interest MCQ with Answers PDF for IBPS

Compound Interest verbal ability questions and answers solutions with PDF for IBPS RRB PO. Aptitude Objective MCQ Practice Exercises all competitive exams

02-Jul-2024 by Careericons

Continue Reading »

100+ Mixture and Alligation MCQ Questions PDF for IBPS

Most importantly Mixture and Alligation multiple choice questions and answers with PDF for IBPS RRB PO. Aptitude MCQ Practice Exercises all Bank Exams

02-Jul-2024 by Careericons

Continue Reading »

IBPS Profit and Loss Questions Solved Problems with PDF

Most important Profit and Loss multiple choice questions and answers with PDF for IBPS RRB PO. 100+ Aptitude MCQ Practice Exercises all competitive exams

28-Jun-2024 by Careericons

Continue Reading »

100+ Average Aptitude Questions Answers solutions MCQ PDF

New Average multiple choice questions and answers with PDF for IBPS RRB PO. 100+ Quantitative Aptitude MCQ Practice Exercises all competitive exams

28-Jun-2024 by Careericons

Continue Reading »