type 5 shares & partnership based ratio & proportion problems Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (a)

$2/5A + 40 = 2/7B + 20$

= $9/17 C + 10 = x$

A = $5/2(x - 40)$, B = $7/2(x - 20)$

and, C = $17/9(x -10)$

$5/2(x - 40) + 7/2(x - 20) + 17/9(x -10)$ = 600

x = 100

A’s share

= Rs.$5/2$(100 - 40) = Rs.150

Answer: (a)

Suppose amount received by men = 5x.

and amount received by women = 4x

According to question

5x + 4x = 180

9x = 180 ⇒ x = 20

Amount received by men = Rs.100

Amount received by women= Rs.80

Suppose the number of men be y and that of women be (66 - y).

According to question

${100/y}/{80/{66 - y}} = 3/2$

$100/y × {66 - y}/80 = 3/2$

${5(66 - y)}/{4y} = 3/2$

660 - 10y = 12y

22y = 660 ⇒ y = 30

Answer: (c)

A = B × $2/9 = {2B}/9$

$C= {3A}/4 ; A = 4/3C$

Ratio of A : B : C = 4 : 18 : 3

Share of A = $4/25 × 1250$ = Rs.200

Share of B = $18/25 × 1250$ = Rs.900

Share of C = $3/25 × 1250$ = Rs.150