type 5 shares & partnership based ratio & proportion problems Section-Wise Topic Notes With Detailed Explanation And Example Questions
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The following question based on ratio & proportion topic of quantitative aptitude
(a) 200, 300, 400
(b) 400, 150, 350
(c) 350, 450, 100
(d) 300, 400, 200
The correct answers to the above question in:
Answer: (a)
A × $1/2 = B × 1/3 = C × 1/4$
$A/2 = B/3 = C/4$
A : B : C = 2 : 3 : 4
A ⇒ $2/9 × 900$ = Rs.200
B ⇒ $3/9 × 900$ = Rs.300
C ⇒ $4/9 × 900$ = Rs.400
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Read more shares and partnership based ratio and proportion Based Quantitative Aptitude Questions and Answers
Question : 1
A sum of 86, 700 is to be divided among A, B and C in such a manner that for every rupee that A gets, B gets 90 paise and for every rupee that B gets, C gets 100 paise. B’s share will be
a) 28,000
b) 28, 090
c) 27,000
d) 26, 010
Answer »Answer: (c)
When A gets 100 paise, B gets 90 Paise
When B gets 100 paise, C gets 110 paise
When B gets 90 paise, C gets
$110/100 × 90$ = 99 paise
A : B : C = 100 : 90 : 99
Sum of the ratios
= 100 + 90 + 99 = 289
B’ share
= $(90/289 × 86700)$ = Rs.27000
Question : 2
A sum of 1240 is distributed among A, B and C such that the ratio of amount received by A and B is 6 : 5 and that of B and C is 10 : 9 respectively. Find the share of C.
a) 400
b) 630
c) 360
d) 480
Answer »Answer: (c)
A : B = 6 : 5, B : C = 10 : 9
A : B : C = 6 : 5 |
10 : 9 |
60 : 50 : 45= 12 : 10 : 9 |
(12 + 10 + 9) units ⇒ 1240
9 units = $1240/31 × 9$ = Rs.360
Question : 3
A sum of 9000 is to be distributed among A, B and C in the ratio 4 : 5 : 6. What will be the difference between A’s and C’s shares?
a) 900
b) 1200
c) 1000
d) 600
Answer »Answer: (b)
A’s share = $9000 × 4/15$
= 600 × 4 = Rs.2400
C’s share = $9000 × 6/15$
= 600 × 6 = Rs.3600
Difference = 3600 - 2400 = Rs.1200
Question : 4
3,000 is divided between A, B and C, so that A receives 1 3 as much as B and C together receive and B receives 2 3 as much as A and C together receive. Then the share of C is
a) 1,625
b) 1,050
c) 525
d) 600
Answer »Answer: (b)
A = $1/3$(B + C)
3A = B + C...(i)
B = $2/3$(A + C)
3B = 2A + 2C ...(ii)
From equation (i),
3A = B + C
9A = 3B + 3C
9A = 2A + 2C + 3C
7A = 5C ...(iii)
From equation (ii),
3B = $2({5C}/7)$ + 2C
21B = 10C + 14C
21B = 24C
7B = 8C ...(iv)
From equations (iii) and (iv),
C = ${7A}/5 = {7B}/8$
$A/5 = B/8 = C/7$
C’s share
= $7/(5 + 8 + 7) × 3000$
= Rs.$(7/20 × 3000)$ = Rs.1050
Question : 5
A sum of 53 is divided among A, B and C in such a way that A gets 7 more than what B gets and B gets 8 more than what C gets. The ratio of their share is
a) 18 : 25 : 10
b) 15 : 8 : 30
c) 25 : 18 : 10
d) 16 : 9 : 18
Answer »Answer: (c)
B = C + 8
A = C + 8 + 7 = C + 15
C + 15 + C + 8 + C = 53
3C + 23 = 53
3C = 53 - 23 = 30
C = Rs.10
B = C + 8 = 10 + 8 = Rs.18
A = C + 15 = 10 + 15 = Rs.25
A : B : C = 25 : 18 : 10
Question : 6
738 is divided among A, B, C so that their shares are in the ratio of 2 : 3 : 4. B’s share is
a) 264
b) 164
c) 246
d) 328
Answer »Answer: (c)
B's share
= $3/(2 + 3 + 4) × 738$
= $3/9 × 738$ = Rs.246
GET ratio & proportion PRACTICE TEST EXERCISES
type 1 basic concepts of ratio & proportion
type 2 age based ratio & proportion problems
type 3 addition subtraction product on ratio & proportion
type 4 income & expenditure based ratio & proportion problems
type 5 shares & partnership based ratio & proportion problems
type 6 fractions based ratio & proportion problems
type 7 finding sum difference product based ratio & proportion problems
type 8 alligation & mixtures based ratio & proportion problems
type 9 coins & rupees based ratio & proportion problems
ratio & proportion Shortcuts and Techniques with Examples
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