model 3 based on positive and negative exponent Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 5 EXERCISES

Top 10,000+ Aptitude Memory Based Exercises

The following question based on power, indices and surds topic of quantitative aptitude

Questions : What will be the remainder when $252^126+244^152$ is divided by 10 ?

(a) 6

(b) 8

(c) 0

(d) 4

The correct answers to the above question in:

Answer:(c)

Unit's digit in the expansion of $(252)^126$

= $2^2$ = 4 (Remainder on dividing 126 by 4 = 2)

Unit's digit in the expansion of $(244)^152$ = 6

Unit's digit in the expansion of $252^126 + 244^152$ = 0

Required remainder = 0

Practice power, indices and surds (model 3 based on positive and negative exponent) Online Quiz

Discuss Form

Valid first name is required.
Please enter a valid email address.
Your genuine comment will be useful for all users! Each and every comment will be uploaded to the question after approval.

Read more positive and negative exponent Based Quantitative Aptitude Questions and Answers

Question : 1

Which of the following numbers is not a factor of $5^p7^q$ (p ≠ 0, q ≠ 0)

a) 175

b) 735

c) 1225

d) 35

Answer:(b)

35 = 5 × 7

175 = 5 × 5 × 7

1225 = 5 × 5 × 7 × 7

735 = 5 × 7 × 7 × 3

Clearly, 735 is not a factor of $5^p7^q$

Question : 2

If $m^n$ = 169, what is the value of $(m+1)^(n - 1)$ ?

a) 13

b) 170

c) 196

d) 14

Answer:(d)

$m^n = 169 = 13^2$

m = 13, n = 2

$(m + 1)^{n - 1} = (13 + 1)^{2 - 1}$ = 14

Question : 3

If $27^{2x - 1} = (243)^3$ then the value of x is :

a) 6

b) 9

c) 7

d) 3

Answer:(d)

$27^{2x - 1} = (243)^3$

$(3^3)^{2x - 1} = (3^5)^3$

$(3)^{3{2x - 1}} = (3)^{5×3}$

3(2x - 1) = 5 × 3

or 2x - 1 = 5 ∴ x = 3

Question : 4

If $3^{x+8} = 27^{2x+1}$, the value of x is :

a) 3

b) 1

c) - 2

d) 7

Answer:(b)

$3^{x+8} = 27^{2x+1}$

$3^{x+8} = (3)^{3(2x+1)}$

x + 8 = 6x + 3

5x = 5 ∴ x=1

Question : 5

If $√{3n}$ = 2187 then the value of n is :

a) 14

b) 16

c) 15

d) 13

Answer:(a)

$√{3^n}$ = 2187

$3^{n/2} = (3)^7$

$n/2$ = 7

n = 2 × 7 = 14

Question : 6

A tap is dripping at a constant rate into a container. The level (L cm) of the water in the container is given by the equation L = 2 - $2^t$, where t is time taken in hours. Then the level of water in the container at the start is

a) 1 cm

b) 4 cm

c) 2 cm

d) 0 cm

Answer:(a)

L = 2 - $2^t$

At the start, t = 0

L = 2 - 2° = 2 - 1 = 1 cm

Recently Added Subject & Categories For All Competitive Exams

100+ Quadratic Equation Questions Answers PDF for Bank

Quadratic Equation multiple choice questions with detailed answers for IBPS RRB SO. more than 250 Attitude practice test exercises for all competitive exams

03-Jul-2024 by Careericons

Continue Reading »

IBPS Aptitude Linear Equations MCQ Questions Answers PDF

Linear equations multiple choice questions with detailed answers for IBPS RRB SO. more than 250 Attitude practice test exercises for all competitive exams

03-Jul-2024 by Careericons

Continue Reading »

New 100+ Compound Interest MCQ with Answers PDF for IBPS

Compound Interest verbal ability questions and answers solutions with PDF for IBPS RRB PO. Aptitude Objective MCQ Practice Exercises all competitive exams

02-Jul-2024 by Careericons

Continue Reading »

100+ Mixture and Alligation MCQ Questions PDF for IBPS

Most importantly Mixture and Alligation multiple choice questions and answers with PDF for IBPS RRB PO. Aptitude MCQ Practice Exercises all Bank Exams

02-Jul-2024 by Careericons

Continue Reading »