model 6 operations of consecutive numbers (odd, even, square, etc.) Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (d)

According to the question,

First number = a = 103; Last number = l = 998

If the number of such numbers be n, then,

998 = 103 + (n – 1) × 5

(n – 1) × 5= 998 – 103 = 895

n – 1 = $895/5$ = 179

n = 180

S = $n/2(a+l)$

=$180/2$(103 +998)

= 90 × 1101 = 99090

Answer: (d)

S = 1 + 3 + 5 + ..... to 50 terms

Here, a = 1; d = 3 – 1 = 2; n = 50

S = $n/2[2a + (n - 1)d]$

= $50/2[2×1+ (50 - 1) ×2]$

= 25 (2 + 98) = 25 × 100 = 2500

Answer: (d)

Sum of five consecutive integers = S

Third integer = $S/5$

Largest integer = $S/5$ + 2 = ${S+10}/5$

Answer: (c)

Numbers divisible by 3 and lying between 100 and 200 are : 102, 105,..... 198

Let number of terms = n

198 = 102 + (n–1) 3

n–1 = ${198 - 102}/3$ = 32

n = 33

S = $n/2$(a+l) =$33/2$(102+ 198) = 4950