Advance Math Model Questions Set 2 Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 2 EXERCISES
The following question based on Advance Math topic of quantitative aptitude
(a) 10
(b) 9
(c) 5
(d) 15
The correct answers to the above question in:
Answer: (b)
For each person to know all the secrets the communication has to be between the Englishmen (who knows say E1 French) and one Frenchmen (say F1). The other two in each case will communicate with E1 & F1 respectively. So for minimum no. of calls, E2 gives information to E1 & receives it after E1 interacts with F1. So 2 calls for each of the four E2, E3, F2 and F3, i.e., 8 calls +1 call (between E1 & F1). Hence 9 calls in all.
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Read more model questions set 2 Based Quantitative Aptitude Questions and Answers
Question : 1
A programmer noted the results of attempting to run 20 programs. The results showed that 2 programs ran correctly in the first attempt, 7 ran correctly in the second attempt, 5 ran correctly in the third attempt, 4 ran correctly in the fourth attempt and 2 ran correctly in the fifth attempt. What is the probability that his next programme will run correctly on the third run ?
a) $1/3$
b) $1/6$
c) $1/4$
d) $1/5$
Answer »Answer: (c)
Total number of attempts = 20
Favourable no. of attempts = 5
Required probability (running the program correctly in the third run) = $5/{20} = 1/4$
Question : 2
In how many ways can four children be made to stand in a line such that two of them, A and B are always together ?
a) 12
b) 18
c) 6
d) 24
Answer »Answer: (a)
Take, A and B to be always together as a single entity.
Now, total no. of children = 4 – 2 + 1 = 3
These can be arranged in 3! ways and A, B can be arranged among themselves in 2! ways.
Hence, no. of arrangements such that A and B are always together = 3! × 2! = 3 × 2 × 2 = 12
Question : 3
A committee consists of 9 experts taken from three institutions A, B and C, of which 2 are from A, 3 from B and 4 from C. If three experts resign, then the probability that they belong to different institutions is:
a) $1/{24}$
b) $1/{21}$
c) $1/{729}$
d) $2/7$
Answer »Answer: (d)
Required probability = ${^2C_1 × ^3C_1 × ^4C_1}/{^9C_3}$
= ${2 × 3 × 4}/{{9!}/{6!3!}} = 2/7$
Question : 4
The probability that the 13th day of a randomly chosen month is a Friday, is
a) $1/7$
b) $1/{84}$
c) $1/{12}$
d) $1/{13}$
Answer »Answer: (b)
Probability of selecting a month = $1/{12}$.
$13^{th}^$ day of the month is friday if its first day is sunday and the probability of this = $1/7$.
∴ Required probability = $1/{12}.1/7 = 1/{84}$.
Question : 5
One bag contains 4 white balls and 2 black balls. Another bag contains 3 white balls and 5 black balls. If one ball is drawn from each bag, determine the probability that one ball is white and another is black.
a) $5/24$
b) $7/24$
c) $6/24$
d) $13/24$
Answer »Answer: (d)
Probability that first ball is white and second black
= (4/6) × (5/8) = 5/12
Probability that first ball is black and second white
= (2/6) × (3/8) = 1/8
These are mutually exclusive events hence the required probability
P = $5/{12} + 1/8 = {13}/{24}$.
Question : 6
There are 6 different letters and 6 correspondingly addressed envelopes. If the letters are randomly put in the envelopes, what is the probability that exactly 5 letters go into the correctly addressed envelopes ?
a) $1/6$
b) $1/2$
c) Zero
d) $5/6$
Answer »Answer: (c)
As there are 6 letters and envelopes, so if exactly 5 are into correctly addressed envelopes, then the remaining 1 will automatically be placed in the correctly addressed envelope. Thus, the probability that exactly 5 go into the correctly addressed envelope is zero.
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