Advance Math Model Questions Set 1 Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 2 EXERCISES
The following question based on Advance Math topic of quantitative aptitude
(a) $7/{19}$
(b) ${12}/{19}$
(c) $4/{19}$
(d) ${21}/{95}$
The correct answers to the above question in:
Answer: (a)
P (None is defective) = ${^{16}C_2}/{^{20}C_2} = ({16 × 15}/{2 × 1} × {2 × 1}/{20 × 19})$
= ${12}/{19}.$
P (at least one is defective) = 1 - ${12}/{19} = 7/{19}$
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Read more model questions set 1 Based Quantitative Aptitude Questions and Answers
Question : 1
3 digits are chosen at random from 1,2,3,4,5,6,7,8 and 9 without repeating any digit. What is the probability that their product is odd?
a) $5/108$
b) $5/42$
c) $2/3$
d) $8/42$
Answer »Answer: (b)
Let E be the event of selecting the three numbers such that their product is odd and S be the sample space. For the product to be odd, 3 numbers choosen must be odd.
∴ n(E) = $^5C_3$
= n(S) = $^9C_3$
∴ P(E) = ${n(E)}/{n(S)} = {^5C_3}/{^9C_3} = 5/{42}$
Question : 2
In a chess tournament, where the participants were to play one game with another, two chess players fell ill, having played 3 games each. If the total number of games played is 84, the number of participants at the beginning was
a) 16
b) 20
c) 15
d) 21
Answer »Answer: (c)
Let there be n participants in the beginning. Then the number of games played by (n – 2) players = $^{n - 2}C_2$
∴ $^{n - 2} C_2 + 6 = 84$
(Two players played three games each)
⇒$^{n - 2}C_2$ = 78⇒(n - 2)(n - 3) = 156
⇒$n^2$ - 5n - 150 = 0
⇒$n^2$ - 15n + 10n = 150 = 0
⇒n(n - 15) + 10(n - 15) = 0
(n - 15)(n + 10) = 0
n = 15, –10
n cannot be –ve
Therefore n = 15.
Question : 3
There are two identical red, two identical black and two identical white balls. In how many different ways can the balls be placed in the cells (each cell to contain one ball) shown below such that balls of the same colour do not occupy any two consecutive cells ?
![advance math aptitude mcq a 62](https://careericons.com/adminicon/bunch/images/advance-math-aptitude-mcq-a-62.png)
a) 18
b) 24
c) 15
d) 30
Answer »Answer: (b)
Let us start with Red colour
Where, R = Red, B = Black, W = White
R | B | R | W |
R | W | R | B |
R | B | R | B |
R | W | R | W |
R | B | W | R |
R | W | B | R |
R | B | B | R |
R | W | W | R |
There are eight such arrangements, if we start with Red ball. Similarly, there are 8 arrangements, if we start with black or white ball.
Hence, No. of arrangements = 8 + 8 + 8 = 24
Question : 4
To fill a number of vacancies, an employer must hire 3 programmers from among 6 applicants, and 2 managers from among 4 applicants. What is the total number of ways in which she can make her selection ?
a) 132
b) 120
c) 1,490
d) 60
Answer »Answer: (b)
Required no. of the ways = $^6C_3 × ^4C_2$ = 20 × 6 = 120
Question : 5
A car is parked by an owner amongst 25 cars in a row, not at either end. On his return he finds that exactly 15 places are still occupied. The probability that both the neighbouring places are empty is
a) ${15}/{184}$
b) ${15}/{92}$
c) ${91}/{276}$
d) None
Answer »Answer: (b)
Exhaustive number of cases = $^{24}C_{14}$
Favourable cases = $^{22}C_{14}$
Probability = ${^{22}C_{14}}/{^{24}C_14} = {15}/{92}$
Question : 6
Ram and Shyam appear for an interview for two vacancies in an organisation for the same post. The probabilities of their selection are 1/6 and 2/5 respectively. What is the probability that none of them will be selected ?
a) $1/5$
b) $1/2$
c) $5/6$
d) $3/5$
Answer »Answer: (b)
Required probability = $(1 - 1/6) × (1- 2/5) = 5/6 × 3/5 = 1/2$
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