Alligation & Mixtures Model Questions Set 1 Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 1 EXERCISES
The following question based on Alligation & Mixtures topic of quantitative aptitude
(a) 4 : 5 : 7
(b) 13 : 7 : 9
(c) 1 : 2 : 3
(d) 12 : 7 : 7
e) None of these
The correct answers to the above question in:
Answer: (d)
1st wheat 120
2nd wheat 144 3rd wheat 174
following the above rule, we have, [(144 – 141) + (174 – 141)]
[= 141 – 120]
![alligations-and-mixtures-mcq-problems-competitive-exams-quantitative-aptitude alligations-and-mixtures-mcq-problems-competitive-exams-quantitative-aptitude](https://careericons.com/adminicon/bunch/images/alligations-and-mixtures-mcq-problems-competitive-exams-3-15.png)
[= 141 – 120]
Therefore, the required ratio = 36 : 21 : 21 = 12 : 7 : 7
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Read more model questions set 1 Based Quantitative Aptitude Questions and Answers
Question : 1
A trader has 50 kg of rice, a part of which he sells at 14% profit and the rest at 6% loss. On the whole his loss is 4%. What is the quantity sold at 14% profit and that at 6% loss?
a) 4, 46
b) 7, 43
c) 2, 48
d) 5, 45
e) None of these
Answer »Answer: (d)
![alligations-and-mixtures-mcq-problems-competitive-exams-quantitative-aptitude alligations-and-mixtures-mcq-problems-competitive-exams-quantitative-aptitude](https://careericons.com/adminicon/bunch/images/alligations-and-mixtures-mcq-problems-competitive-exams-3-7.png)
Question : 2
A can contains a mixture of two liquids A and B in the ratio 7 : 5. When 9 litres of mixture are drawn off and the can in filled with B, the ratio of A and B becomes 7 : 9. How many litres of liquid A was contained by the can initially?
a) 20
b) 25
c) 10
d) 21
e) None of these
Answer »Answer: (d)
Suppose the can initially contains 7x and 5x litres of mixtures A and B respectively.
Quantity of A mixture left = $(7x - {7/{12}} × 9) litres = (7x - {{21}/4})$
Quantity of B in mixture left = $(5x - {5/{12}} × 9)$ litres
= $(5x - {{15}/4})$ litres.
∴ ${(7x-{{21}/4})}/{(5x-{15/4}) + 9} = 7/9⇒{28x - 21}/{20x + 21} = 7/9$
⇒252x – 189 = 140x + 147
⇒112 x = 336⇒x = 3.
So, the can contained 21 litre
Question : 3
How many kg of salt at 42 P per kg must a man mix with 25 kg of salf at 24 P per kg so that he may, on selling the mixture at 40 P per kg gain 25% on the outlay?
a) 20
b) 30
c) 15
d) 25
e) None of these
Answer »Answer: (a)
Cost price of mixture = 40 × ${100}/{125}$P = 32P per kg
By the rule of fraction
![alligations-and-mixtures-mcq-problems-competitive-exams-quantitative-aptitude alligations-and-mixtures-mcq-problems-competitive-exams-quantitative-aptitude](https://careericons.com/adminicon/bunch/images/alligations-and-mixtures-mcq-problems-competitive-exams-3-2.png)
Ratio = 4 : 5
Thus, for every 5 kg of salt at 24 P, 4 kg of salt at 42P is used.
∴ the required no. of kg = 25 × $4/5$ = 20.
Question : 4
300 gm of sugar solution has 40% sugar in it. How much sugar should be added to make it 50% in the solution?
a) 50 gm
b) 70 gm
c) 40 gm
d) 60 gm
e) None of these
Answer »Answer: (d)
The existing solution has 40% sugar. And sugar is to be mixed;
so the other solution has 100% sugar. So, by alligation method:
![alligations-and-mixtures-mcq-problems-competitive-exams-quantitative-aptitude alligations-and-mixtures-mcq-problems-competitive-exams-quantitative-aptitude](https://careericons.com/adminicon/bunch/images/alligations-and-mixtures-mcq-problems-competitive-exams-3-1.png)
∴ The two mixtures should be added in the ratio 5 : 1.
Therefore, required sugar = ${300}/5$ × 1 = 60 gm
Question : 5
Milk and water are mixed in a vessel A in the proportion 5 : 2, and in vessel B in the proportion 8 : 5. In what proportion should quantities be taken from the two vessels so as to form a mixture in which milk and water will be in the proportion of 9 : 4?
a) 5 : 7
b) 7 : 9
c) 4 : 5
d) 7 : 2
e) None of these
Answer »Answer: (d)
In vessel A, milk = $5/7$ of the weight of mixture
In vessel B, milk = $8/{13}$ of the weight of mixture. Now, we
want to form a mixture in which milk will be $9/{13}$ of the weight of this mixture.
By alligation rule:
![alligations-and-mixtures-mcq-problems-competitive-exams-quantitative-aptitude alligations-and-mixtures-mcq-problems-competitive-exams-quantitative-aptitude](https://careericons.com/adminicon/bunch/images/alligations-and-mixtures-mcq-problems-competitive-exams-3-17.png)
∴ required proportion is $1/{13} : 2/{91}$ = 7 : 2
Question : 6
A person has a chemical of Rs. 25 per litre. In what ratio should water be mixed in that chemical so that after selling the mixture at Rs. 20/litre he may get a profit of 25%?
a) 15
b) 17
c) 14
d) 16
e) None of these
Answer »Answer: (d)
In this question, the alligation method is applicable on prices,
so we should get the average price of mixture.
SP of mixture = Rs.20/litre; profit = 25%
∴ average price = 20 × ${100}/{125}$ = Rs. 16/litre
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