Squareroots & Cuberoots Model Questions Set 1 Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 1 EXERCISES
The following question based on Squareroots & Cuberoots topic of quantitative aptitude
(a) 1296
(b) 1024
(c) 1156
(d) 1089
e) None of these
The correct answers to the above question in:
Answer: (c)
(74 × $√{676}) - 42 × √{?} = 496$
$√{?} =(74 × 26 - 496)/42 = 1428 ÷ 42 = 34= (34)^2$ = 1156
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Question : 1
7365 + $(5.4)^2 + √{?}$ = 7437.16
a) 1681
b) 1894
c) 1764
d) 2025
e) None of these
Answer »Answer: (e)
7365 + 29.16 + $√{?}$ = 7437.16
$√{?}$ = 473.16 – 7394.16
$√{?}$ = 43 = 1849
Question : 2
What is the least number to be added to 2000 to make it a perfect square?
a) 64
b) 25
c) 36
d) 49
e) None of these
Answer »Answer: (b)
4 4 | 2000 16 | 45 |
85 5 | 400 425 | |
- 25 |
Clearly, the required least number is 25.
Question : 3
The least number to be subtracted from 24136 to make it a perfect square
a) 111
b) 155
c) 156
d) None of these.
Answer »Answer: (a)
Let us extract the square root from 24136.
![square-roots-and-cube-roots-mcq-problems-quantitative-aptitude square-roots-and-cube-roots-mcq-problems-quantitative-aptitude](https://careericons.com/adminicon/bunch/images/square-roots-and-cube-roots-mcq-problems-6.png)
∴ 24136, is 111 more than $(155)^2$ .
So if we subtract 111 from 24136, we will get a perfect sq. number.
Question : 4
The three numbers are in the ratio 2 : 3 : 4. The sum of their cubes is 33957. The numbers are,
a) 4, 6, 8
b) 6, 9, 12
c) 12, 18, 24
d) 14, 21, 28
Answer »Answer: (d)
Let the ratio of numbers be x.
∴ numbers are 2x, 3x & 4x.
∴$(2x)^3+(3x)^3+(4x)^3$=33957
⇒$8x^3+27x^3+64x^3$=33957
⇒$99x^3$=33957
⇒$x^3=33957/99$
⇒$x^3$=343⇒x=7
∴ Numbers are 2×7,3×7,4×7
i.e. 14, 21, 28
Question : 5
You have a rectangular frame that is 40 cm by 60 cm. Can you put a square picture that has an area of 800 $cm^2$ completely inside the frame?
a) No
b) Yes
c) Can't say
d) Data insufficient
Answer »Answer: (b)
Question : 6
The area of a circular play ground is ${3168}/{7}m^2$ . The diameter of the ground is
a) 22 m
b) 12 m
c) 24 m
d) 6 m
Answer »Answer: (b)
Area = $πr^2=3168/7$
$r^2 = {3168}/7×7/{22}$=144
$r =√144$ = 12m
Diameter = 24 m
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