Squareroots & Cuberoots Model Questions Set 1 Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 1 EXERCISES

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The following question based on Squareroots & Cuberoots topic of quantitative aptitude

Questions : $(74 × √676)- (42 × √{?})$ = 496

(a) 1296

(b) 1024

(c) 1156

(d) 1089

e) None of these

The correct answers to the above question in:

Answer: (c)

(74 × $√{676}) - 42 × √{?} = 496$

$√{?} =(74 × 26 - 496)/42 = 1428 ÷ 42 = 34= (34)^2$ = 1156

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Read more model question set 1 Based Quantitative Aptitude Questions and Answers

Question : 1

7365 + $(5.4)^2 + √{?}$ = 7437.16

a) 1681

b) 1894

c) 1764

d) 2025

e) None of these

Answer: (e)

7365 + 29.16 + $√{?}$ = 7437.16

$√{?}$ = 473.16 – 7394.16

$√{?}$ = 43 = 1849

Question : 2

What is the least number to be added to 2000 to make it a perfect square?

a) 64

b) 25

c) 36

d) 49

e) None of these

Answer: (b)

4
4
2000
16
45
85
5
400
425
 
 - 25 

Clearly, the required least number is 25.

Question : 3

The least number to be subtracted from 24136 to make it a perfect square

a) 111

b) 155

c) 156

d) None of these.

Answer: (a)

Let us extract the square root from 24136.

square-roots-and-cube-roots-mcq-problems-quantitative-aptitude

∴ 24136, is 111 more than $(155)^2$ .

So if we subtract 111 from 24136, we will get a perfect sq. number.

Question : 4

The three numbers are in the ratio 2 : 3 : 4. The sum of their cubes is 33957. The numbers are,

a) 4, 6, 8

b) 6, 9, 12

c) 12, 18, 24

d) 14, 21, 28

Answer: (d)

Let the ratio of numbers be x.

∴ numbers are 2x, 3x & 4x.

∴$(2x)^3+(3x)^3+(4x)^3$=33957

⇒$8x^3+27x^3+64x^3$=33957

⇒$99x^3$=33957

⇒$x^3=33957/99$

⇒$x^3$=343⇒x=7

∴ Numbers are 2×7,3×7,4×7

i.e. 14, 21, 28

Question : 5

You have a rectangular frame that is 40 cm by 60 cm. Can you put a square picture that has an area of 800 $cm^2$ completely inside the frame?

a) No

b) Yes

c) Can't say

d) Data insufficient

Answer: (b)

Question : 6

The area of a circular play ground is ${3168}/{7}m^2$ . The diameter of the ground is

a) 22 m

b) 12 m

c) 24 m

d) 6 m

Answer: (b)

Area = $πr^2=3168/7$

$r^2 = {3168}/7×7/{22}$=144

$r =√144$ = 12m

Diameter = 24 m

GET Squareroots & Cuberoots PRACTICE TEST EXERCISES

Squareroots & Cuberoots Model Questions Set 1

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