Squareroots & Cuberoots Model Questions Set 1 Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on Squareroots & Cuberoots topic of quantitative aptitude

Questions : $(13)^2 - (5)^2 - √676 +7 = (?)^2$

(a) 20

(b) 10

(c) $√5$

(d) $(25)^2$

e) 5

The correct answers to the above question in:

Answer: (e)

169 – 25 – 26 + 7 = $(?)^2 = 125 = ?^2⇒? = √125 = 5 √5$

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Read more model question set 1 Based Quantitative Aptitude Questions and Answers

Question : 1

The hypotenuse of an isosceles right angled triangular field has a length of $30√2$ m, the length of other side is

a) 30 m

b) $30√2$

c) 25 m

d) None of these

Answer: (a)

square-roots-and-cube-roots-mcq-problems-quantitative-aptitude

$(30√2)^2=a^2+a^2$

1800=$2a^2$

$a^2$=900

a = 30m

Question : 2

$(13)^2 - (4)^3$ - $√{676}$ + 2 = $(?)^2$

a) 9

b) 3

c) 81

d) 27

e) 18

Answer: (a)

169 – 64 – $√{676} + 2 = (?)^2$

= 169 – 64 – 26 + 2 = $(?)^2$ = 171 – 90 = 81

∴ ? = 9

Question : 3

$(656 ÷ 164)^2 = √{?}$

a) 16

b) 14

c) 64

d) 256

e) None of these

Answer: (d)

$√{?}=4^2$ =16

∴? = 256

Question : 4

1190 ÷ $√7225$ × ? = 3094 =

a) 121

b) 221

c) 214

d) 241

e) None of these

Answer: (b)

$1190/√{7225}$ ×? = 3094 = or, ${1190 × ?}/85$ = 3094

or, ? = ${3094 × 85}/1190$ = 221

Question : 5

$√{12 × 145 ÷ 6 + 34}$ = ?

a) $(324)^2$

b) – 18

c) 18

d) $√18$

e) None of these

Answer: (c)

Question : 6

The smallest number by which 3888 must be divided so that the resulting number is a perfect square is

a) 6

b) 2

c) 3

d) None of these.

Answer: (c)

Resolving 3888 into its prime factors, we find that

3888=2×2×2×2×3×3×3×3×3

3888 = (2×2) × (2×2) × (3×3) × (3×3) ×3

Here we find that prime factor 3 is appearing alone.

So, if we divide 3888 by 3, we will get a perfect square number

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Squareroots & Cuberoots Model Questions Set 1

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