Statistics Model Questions Set 1 Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 1 EXERCISES

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The following question based on Statistics topic of quantitative aptitude

Questions : An individual purchases three qualities of pencils. The relevant data is given below :
QualityPrice per Pencil (in Rs.)Money spent (in Rs.)
A1.0050
B1.50x
C2.0020
It is known that the average price per pencil is Rs.1.25. What is the value of x ?

(a) Rs. 30

(b) Rs.40

(c) Rs.10

(d) Rs.60

The correct answers to the above question in:

Answer: (a)

Number of Type A pencil = ${50}/1$ = 50

Number of Type B pencil = $x/{1.50}$

Number of Type C pencil = ${20}/2$ = 10

Average = ${\text"Total money spent"}/{\text"totalno.of pencil"}$ = 1.25

= ${x + 50 + 20}/{50 + 10 + {x/{1.50}}}$ = 1.25

= 70 + x = 1.25 $(60 + x/{1.50})$

70 + x = 75.00 + ${1.25}/{1.50}$x

x - ${125}/{150}$ x = 5

= ${25}/{150}$ x = 5

x = 30

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Read more model question set 1 Based Quantitative Aptitude Questions and Answers

Question : 1

The following table gives the frequency distribution of life length in hours of 100 electric bulbs having median life 20 h.

Life of bulbs(in hours)Number of bulbs
8-137
13-18x
18-2340
23-28y
28-3310
33-382
What is the missing frequency 'y'?

a) 24

b) 14

c) 27

d) 11

Answer: (b)

Number of total bulbs = 100

∴ 7 + x + 40 + y + 10 + 2 = 100

⇒ x + y = 41 ... (i)

Life of bulbs (in hours)Number of bulbsCumulative Frequency
8 - 1377
13 - 18x7 + x
18 - 234047 + x
23 - 28y47 + x + y
28 - 331057 + x + y
33 - 38259 + x + y
 N = 100 

The median life is 20 h, so median interval will be (18-23).

Here, l = 18, $N/2$ = 50

c = 7 + x, f = 40, h = 5

∴ Median = l + ${(N/2 - C)}/f$ × h

⇒ 20 = 18 + ${(50 – 7 – x)}/{40}$ × 5

⇒ 2 = ${50 – 7 – x}/8$

⇒ 16 = 50 – 7 – x

⇒ x = 43 – 16

⇒ x = 27

Missing frequency 'y' is 14.

Question : 2

What is the difference between the number of boys studying Mathematics and the number of girls studying Physics?

a) 30

b) 60

c) 20

d) 80

Answer: (a)

Difference in the number of boys studying Mathematics and Physics = 180 – 150 = 30

Question : 3

Read the following information carefully to answer the questions that follow. The average age of 6 persons living in a house is 23.5 years. Three of them are majors and their average age is 42 years. The difference in ages of the three minor children is same.What is the median of the ages of minor children?

a) 5 years

b) 7 years

c) 3 years

d) Cannot be determined

Answer: (a)

Total age of six persons = 23.5 × 6 = 141 years

Total age of three major persons = 42 × 3 = 126 years

∴ Total age of three minor children = 141 – 126 = 15 years

The difference in ages of the three minor children is same.

Therefore, we take ages may be:

5, 5, 5; 3, 5, 7; 2, 5, 8 and 1, 5, 9

In all the cases, median will be 5 years.

Median age of minor children = 5 years.

Question : 4

If each of n numbers xi = i (i = 1, 2, 3,..... n) is replaced by (i + 1) $x_i$ , then the new mean is

a) ${n(n + 1)}/2$

b) ${(n + 1)(n + 2)}/{3n}$

c) ${n + 3}/2$

d) ${(n + 1)(n + 2)}/3$

Answer: (d)

$(i + 1)x^i = (i + 1)x^i$ where i = 1, 2, 3, ------- n

$Σ↖{n}↙{i = 1}(i + 1)$ = 1.2 + 2.3 + 3.4 + 4.5 + -------meters

= $Σ↖{n}↙{n = 1} T_n$

= Σ n (n + 1)

= $Σn^2 + Σn$

= ${(n + 1)n(2n + 1)}/6 + {n(n + 1)}/2$

Mean = $1/n [{(n + 1) n (2n + 1)}/6 + {n(n + 1)}/2]$

= ${(n + 1)}/2 [{2n + 1}/3 + 1]$

= ${(n + 1)}/2 {(2n + 4)}/3$

= ${(n + 1)(n + 2)}/3$

So, option (d) is correct.

Question : 5

Which one among the following statements is not correct?

a) For average rate of increase when the rate of population growth is given, geometric mean is best suitable

b) For average rate of speed when different distances are covered by different rates of speed, harmonic mean is best suitable

c) For size of readymade garments, mode is the best suitable measure

d) For average level of intelligence of students in a class, arithmetic mean is the best suitable

Answer: (d)

Since, intelligence of students is an attribute, arithmetic mean is not suitable method.

Question : 6

What is the mode of the frequency distribution of SeriesII?

a) 36

b) 46

c) 26

d) 56

Answer: (b)

Mode of frequency distribution of series II is 46.

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Statistics Model Questions Set 1

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