Logarithm Model Questions Set 1 Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on Logarithm topic of quantitative aptitude

Questions : If ${\text"log"_7}{\text"log"_5} (√x + 5 + √x)$ = 0 , find the value of x.

(a) 2

(b) 1

(c) – 2

(d) 0

e) None of these

The correct answers to the above question in:

Answer: (d)

$\text"log"_7 \text"log"_5(√x + 5 + √x)$ = 0

use $\text"log"_a$ x = b⇒$a^b$=x

∴ $\text"log"_5 (√x + 5 + √x) = 7^0$ = 1

$√x + 5 + √ x = 5^1 = 5⇒2√x$ = 0

∴ x = 0

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Read more model question set 1 Based Quantitative Aptitude Questions and Answers

Question : 1

$\text"log" 216 √6$ to the base 6 is

a) 7/2

b) 3

c) 2/7

d) 3/2

e) None of these

Answer: (a)

$\text"log"_{6} 216 √6 = \text"log"_6 (6)^3 (6)^{1/2}$

= $\text"log"_6 (6)^{7/2} = {7/2}{ \text"log"_6} 6 = 7/2$ (∵ $\text"log"_a$ a = 1)

Question : 2

What is the number of digits in $7^{25}, 8^{23} and 9^{20}$ respectively ? [Given $log_{10}2 = 0.301, log_{10}3 = 0.477, log_{10}7 = 0.845$]

a) 22, 21, 20

b) 21, 20, 19

c) 20, 19, 18

d) 22, 20, 21

Answer: (d)

$log 7^{25}$ = 25 log 7 = 25 × 0.845

= 21.125

Its characteristic is 21⇒No. of digits = 22

$log 8^{23} = log 2^{69}$ = 69 log 2

= 69 × 0.301 = 20.769

Its characteristic is 20⇒No. of digits = 21

$log 9^{20} = log 3^{40}$

= 40 × log3

= 40 × 0.477 = 19.08⇒No. of digits = 20

Near about is 22, 21, 20 so option (d) satisfy

Question : 3

What is the value of ${[log_{13}(10)]}/{[log_{169}(10)]}$

a) 1

b) $1/2$

c) 2

d) $log_{10}13$

Answer: (c)

${log_{13}(10)}/{log_{169}(10)} = {log_{13}(10)}/{log_{13^2}(10)}$

$(∵ log_{a^b} c = 1/b log_a c)$

= ${log_{13}10}/{1/2 log_{13}10} = 1/{1/2}$ = 2

Question : 4

What is the number of digits in $2^{40}$ ? (Given that $log_{10} 2$ = 0.301)

a) 12

b) 14

c) 13

d) 11

Answer: (c)

let $2^{40} = 10^x$

log $2^{40} = log 10^x$

40 $log^2 = x log^{10}$

40 (.301) = x

12.04 = x

i.e. x > 12

∴ x = 13

No. of digit in $2^{40}$ is 13

Question : 5

What is the logarithm of 0.0001 with respect to base 10?

a) –4

b) 4

c) 3

d) –3

Answer: (a)

Let $log_{10}$ 0.0001 = a

a = $log_{10} {1/{(10)^4}$

= $log_{10} 1 – log_{10} (10)^4$ = 0 – 4 = –4

Question : 6

Let XYZ be an equilateral triangle in which XY = 7 cm. If A denotes the area of the triangle, then what is the value of $log_{10}A^4$ ? (Given that $log_{10}1050 = 3.0212$ and $log_{10}35$ = 1.5441)

a) 5. 5635

b) 5. 3070

c) 5. 3700

d) 5. 6535

Answer: (b)

$log_{10} 1050 = log_{10}$(3 × 10 × 35)

= $log_{10} 3 + 1 + log_{10} 35$

⇒ 3.0212 = $log_{10} 3 + 1 + 1.5441$

⇒$log_{10} 3$ = 0.4771

Now, $log_{10} 35 = log {7 × 10}/2$

= $log_{10} 7 + log_{10} - log_{10} 2$

⇒ $log_{10}7$ = 0.8451

Now, A = ${√3}/4 × (7)^2$

$log{10^A^4} = 4 log_{10}A$

= 4 log ${√3 × 7^2}/4$

= $4[1/2 log_3 + 2 log_{10} 7 - 2 log 2]$ = 5.3070

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Logarithm Model Questions Set 1

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