type 7 finding sum difference product based ratio & proportion problems Section-Wise Topic Notes With Detailed Explanation And Example Questions
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The following question based on ratio & proportion topic of quantitative aptitude
(a) 1, 2, 3
(b) 5, 10, 15
(c) 15, 30, 45
(d) 10, 20, 30
The correct answers to the above question in:
Answer: (b)
Numbers = x, 2x and 3x
${x + 5}/{2x + 5}= 2/3$
4x + 10 = 3x + 15
x = 5
Numbers = 5, 10 and 15
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Read more finding sum difference product problems Based Quantitative Aptitude Questions and Answers
Question : 1
The students in three classes are in the ratio 2 : 3 : 5. If 40 students are increased in each class, the ratio changes to 4 : 5 : 7. Originally, the total number of students was :
a) 200
b) 400
c) 180
d) 100
Answer »Answer: (a)
Let the number of students in three classes be 2x, 3x and 5x respectively.
Due to increase of 40 students in each class,
we have ${2x + 40}/{3x + 40} = 4/5$
10x + 200 = 12x + 160
2x = 200 - 160
2x = 40 ⇒ x = 20
Original strength
= 10x = 10 × 20 = 200
Question : 2
What must be added to each term of the ratio 7 : 11, so as to make it equal to 3 : 4 ?
a) 6.5
b) 5
c) 7.5
d) 8
Answer »Answer: (b)
Let the required number be x.
${7 + x}/{11 + x} = 3/4$
28 + 4x = 33 + 3x
x = 33 - 28 = 5
Question : 3
The ratio of the number of boys and girls of a school with 504 students is 13 : 11. What will be the new ratio if 12 more girls are admitted?
a) 9 : 10
b) 10 : 9
c) 81 : 91
d) 91 : 81
Answer »Answer: (d)
Total numbers of girls in the school
= $504 ×11/{13 + 11}$
= $504 × 11/24$ = 231
Total numbers of boys in the school
= $504 × 13/{13 + 11}$
= $504 × 13/29 = 273$
Now, total no. of girls when 12 more girls are admitted
= 231 + 12 = 243
Required ratio
= 273 : 243 = 91 : 81
Question : 4
The ratio of the number of ladies to that of gents at a party was 3 : 2. When 20 more gents joined the party, the ratio was reversed. The number of ladies present at the party was
a) 24
b) 16
c) 32
d) 36
Answer »Answer: (a)
Let the number of ladies and gents be 3x and 2x respectively.
According to the question,
${3x}/{2x + 20} = 2/3$
9x = 4x + 40
5x = 40 ⇒ x = 8
Number of ladies = 3x
= 3 × 8 = 24
Question : 5
The total number of students in a school was 660. The ratio between boys and girls was 13 : 9. After some days, 30 girls joined the school and some boys left the school and new ratio between boys and girls became 6 : 5. The number of boys who left the school is :
a) 30
b) 60
c) 40
d) 50
Answer »Answer: (a)
In the first case,
Boys = $660 × 13/22$ = 390
Girls = $660 × 9/22$ = 270
If x boys leave the school, then
${390 - x}/{270 + 30} = 6/5$
390 - x = 360
x = 390 - 360 = 30
Question : 6
The average of 11 numbers is 36, whereas average of 9 of them is 34. If the remaining two numbers are in the ratio of 2 : 3, find the value of the smaller number (between remaining two numbers).
a) 54
b) 36
c) 48
d) 45
Answer »Answer: (b)
According to the question,
Sum of remaining two numbers
= 11 × 36 - 9 × 34
= 396 - 306 = 90
Ratio of the remaining two numbers = 2 : 3
Smaller number
= $2/5$ × 90 = 36
GET ratio & proportion PRACTICE TEST EXERCISES
type 1 basic concepts of ratio & proportion
type 2 age based ratio & proportion problems
type 3 addition subtraction product on ratio & proportion
type 4 income & expenditure based ratio & proportion problems
type 5 shares & partnership based ratio & proportion problems
type 6 fractions based ratio & proportion problems
type 7 finding sum difference product based ratio & proportion problems
type 8 alligation & mixtures based ratio & proportion problems
type 9 coins & rupees based ratio & proportion problems
ratio & proportion Shortcuts and Techniques with Examples
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