type 7 finding sum difference product based ratio & proportion problems Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on ratio & proportion topic of quantitative aptitude

Questions : Two numbers are in the ratio 3 : 5. If 9 is subtracted from each, then they are in the ratio 12 : 23. Find the smaller number.

(a) 49

(b) 55

(c) 33

(d) 27

The correct answers to the above question in:

Answer: (c)

Let the numbers be 3x and 5x.

${3x - 9}/{5x - 9} = 12/23$

69x - 60x = 207 - 108

$x =99/9$ 11

The smaller number = 3x = 33

Using Rule 35,

Here, a = 3, b = 5, x= 9, c = 12, d = 23

1st Number = ${xa(d-c)}/{ad-bc}$

= ${9 ×3(23 - 12)}/{3 × 23 - 5 × 12}$

= ${27 × 11}/{69 - 60}$

=${27 × 11}/9$ = 33

2nd Number= ${xb(d-c)}/{ad-bc}$

= ${9 ×5(23 - 12)}/{3 × 23 - 5 × 12}$

= ${45 × 11}/{69 - 60}$

= ${45 × 11}/9$= 55

Smallest number = 33

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Read more finding sum difference product problems Based Quantitative Aptitude Questions and Answers

Question : 1

Three numbers are in the ratio 1 : 2 : 3 and the sum of their cubes is 4500 . The smallest number is

a) 6

b) 10

c) 5

d) 4

Answer: (c)

Let the numbers be x, 2x and 3x.

According to the question,

$x^3 + (2x)^3 + (3x)^3$ = 4500

$x^3 + 8x^3 + 27x^3$ = 4500

$36x^3$ = 4500

$x^3 = 4500/36$ = 125

$x = √^3{125}$= 5 = smallest number

Question : 2

Two numbers are in the ratio 7 : 11. If 7 is added to each of the numbers, the ratio becomes 2 : 3. The smaller number is

a) 66

b) 77

c) 49

d) 39

Answer: (c)

Let the numbers be 7x and 11x respectively.

${7x + 7}/{11x + 7} = 2/3$

22x + 14 = 21x + 21

x = 7

Smaller number

= 7x = 7 × 7 = 49

Using Rule 34
Two numbers are in the ratio a:b and if each number is increased by x, the ratio becomes c:d. Then the two numbers will be
${xa(c-d)}/{ad-bc}$ and ${xb(c-d)}/{ad-bc}$

Here, a = 7, b = 11, x = 7, c= 2, d = 3

1st Number = ${xa(c-d)}/{ad-bc}$

= ${7 × 7(2 - 3)}/{7 × 3 - 11 × 2}$

= ${49 × -1}/{21 - 22}$ = 49

2nd Number = ${xb(c-d)}/{ad-bc}$

= ${7 × 11(2 - 3)}/{7 × 3 - 11 × 2}$

= ${77 × -1}/{21 - 22}$ = 77

Smallest number = 49

Question : 3

Two numbers are such that the ratio between them is 4 : 7. If each is increased by 4, the ratio becomes 3 : 5. The larger number is

a) 56

b) 64

c) 48

d) 36

Answer: (a)

Let the numbers be 4x and 7x.

${4x + 4}/{7x + 4} = 3/5$

21x + 12 = 20x + 20

21x - 20x = 20 - 12

x = 8

Larger number

= 7x = 7 × 8 = 56

Using Rule 34,

a = 4, b = 7, c = 3,

d = 5, x = 4

Larger number = ${xb(c-d)}/{ad-bc}$

= ${4 ×7(3 -5)}/{4 × 5 - 3 × 7}$

= ${4 × 7 × (-2)}/{20 - 21}$= 56

Question : 4

The students in three classes are in the ratio 4 : 6 : 9. If 12 students are increased in each class, the ratio changes to 7 : 9 : 12. Then the total number of students in the three classes before the increase is

a) 100

b) 114

c) 76

d) 95

Answer: (c)

Let the original number of students be 4x , 6x and 9x.

${4x + 12}/{6x +12} = 7/9$

42x + 84 = 36x + 108

42x - 36x = 108 - 84

6x = 24 ⇒ x = 4

Required number of students

= 19x = 19 × 4 = 76

Question : 5

The ratio between two numbers is 2 : 3. If each number is increased by 4, the ratio between them becomes 5 : 7. The difference between the numbers is

a) 4

b) 2

c) 6

d) 8

Answer: (d)

Let the numbers be 2x and 3x.

${2x + 4}/{3x + 4} = 5/7$

15x + 20 = 14x + 28

x = 28 - 20 = 8

Required difference

Using Rule 34,

Here, a = 2, b = 3,c = 5

d = 7 and x = 4

1st Number = ${xa(c-d)}/{ad-bc}$

= ${4 ×2(5 - 7)}/{2 × 7 - 5 × 3}$

= ${8 × - 2}/{14 - 15}$ = 16

2nd Number= ${xb(c-d)}/{ad-bc}$

= ${4 ×3(5 - 7)}/{2 × 7 - 5 × 3}$

= ${4 × 3 (- 2)}/{14 - 15}$ = 24

Difference of numbers = 24 - 16 = 8

Question : 6

Two numbers are in the ratio 1$1/2 : 2{2}/3$. When each of these is increased by 15, they become in the ratio 1$2/3 : 2{1}/2$. The greater of the numbers is :

a) 48

b) 64

c) 36

d) 27

Answer: (a)

Let the numbers be $3/2$x and $8/3$x

According to question,

${3/2 x + 15}/{{8x}/3 + 15} = {5/3}/{5/2}$

${{3x + 30}/2}/{{8x + 45}/3} = 2/3$

${3(3x + 30)}/{2(8x + 45)} = 2/3$

${9x + 90}/{16x + 90} = 2/3$

27x + 270 = 32x + 180

32x - 27x = 270 - 180 = 90

5x = 90 ⇒ x = 18

The greater number

= $8/3 x = 8/3 × 18$ =48

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