type 7 finding sum difference product based ratio & proportion problems Section-Wise Topic Notes With Detailed Explanation And Example Questions
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The following question based on ratio & proportion topic of quantitative aptitude
(a) 100
(b) 150
(c) 90
(d) 50
The correct answers to the above question in:
Answer: (a)
Let the original number of students in three classes be 2x, 3x and 5x respectively.
As given,
${2x + 20}/{3x + 20} = 4/5$
10x + 100 = 12x + 80
12x - 10x = 100 - 80
2x = 20 ⇒ $x = 20/2$ = 10
Total number of students originally
= 2x + 3x + 5x = 10x
= 10 × 10 = 100
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Read more finding sum difference product problems Based Quantitative Aptitude Questions and Answers
Question : 1
The ratio of the number of boys and that of girls in a school having 504 students is 13 :11. What will be the new ratio if 3 more girls are admitted?
a) 10 :11
b) 13 :14
c) 6 : 7
d) 7 : 6
Answer »Answer: (d)
Using Rule 21If an amount R is to be divided between A and B in the ratio m:n then(i) Part of A =$m/{m+n}×R$(ii) Part of B =$n/{m+n}×R$(iii) Difference of part of A and B =${mn}/{m+n}×R$where m > n
Number of boys
= $13/{13 + 11} × 504$
= $13/24 × 504$ = 273
Number of girls
= 504 - 273 = 231
3 girls are admitted.
Required ratio
= 273 : 234 = 7 : 6
Question : 2
Ram got twice as many marks in English as in Science. His total marks in English, Science and Maths are 180. If the ratio of his marks in English and Maths is 2 : 3, what is his marks in Science ?
a) 72
b) 90
c) 60
d) 30
Answer »Answer: (d)
Marks in English = 2x
Marks in Maths = 3x
Marks in Science = x
x + 2x + 3x = 180
6x = 180 ⇒ x = 30
Question : 3
The ratio of number of boys to that of girls in a group becomes 2:1 when 15 girls leave. But, afterwards, when 45 boys also leave, the ratio becomes 1 : 5. Originally the number of girls in the group was
a) 40
b) 50
c) 30
d) 20
Answer »Answer: (a)
Let the original number of boys and girls be x and y respectively.
Then $x/{y - 15} = 2/1$
x = 2y - 30 ....(i)
Again, ${x - 45}/{y - 15} =1/5$
5x - 225 = y - 15
5x = y - 15 + 225
5 (2y - 30) = y + 210
[From equation (i)]
10y - 150 = y + 210
10y - y = 210 + 150
9y = 360 ⇒ $y = 360/9$ = 40
Question : 4
The ratio of two positive numbers is 3 : 4. The sum of their squares is 400. What is the sum of the numbers ?
a) 24
b) 26
c) 22
d) 28
Answer »Answer: (d)
Let two positive numbers be 3x and 4x.
According to the question,
$(3x)^2 + (4x)^2$ = 400
$9x^2 + 16x^2$ = 400
$25x^2$ = 400
$x^2 = 400/25$ = 16
$x = √16$ = 4
Sum of numbers
= 3x + 4x = 7x
= 7 × 4 = 28
GET ratio & proportion PRACTICE TEST EXERCISES
type 1 basic concepts of ratio & proportion
type 2 age based ratio & proportion problems
type 3 addition subtraction product on ratio & proportion
type 4 income & expenditure based ratio & proportion problems
type 5 shares & partnership based ratio & proportion problems
type 6 fractions based ratio & proportion problems
type 7 finding sum difference product based ratio & proportion problems
type 8 alligation & mixtures based ratio & proportion problems
type 9 coins & rupees based ratio & proportion problems
ratio & proportion Shortcuts and Techniques with Examples
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