model 4 find nth average from 1st & last number Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (a)

Sum of remaining 10 numbers

= 12 × 15 – 2 × 14

= 180 – 28 = 152

∴ Required average =$152/10$

= $76/5$ = 15$1/5$

Answer: (d)

Largest 3–digit number formed by 0, 2 and 4 = 420 Smallest number of three digits = 204

∴ Required average

= ${420+204}/2$ = $624/2$ = 312

Answer: (a)

Using Rule 1,

Average of two or more numbers/quantities is called the mean of these numbers, which is given by

$\text"Average(A)" = \text"Sum of observation / quantities"/\text"No of observation / quantities"$

∴ S = A × n

Sixth number

= 6 × 32 + 6 × 37 – 11 × 35

= 192 + 222 – 385 = 29

Answer: (a)

Using Rule 1,

Average of two or more numbers/quantities is called the mean of these numbers, which is given by

$\text"Average(A)" = \text"Sum of observation / quantities"/\text"No of observation / quantities"$

∴ S = A × n

Last number = Sum of 20 numbers

– sum of first 12 numbers – sum of next 7 numbers

= 20 × 12 – 11 × 12 – 7 × 10

= 240 – 132 – 70 = 38

Answer: (a)

Seventh observation

= 65 × 7 + 7 × 75 – 13 × 70

= 455 + 525 – 910

= 980 – 910 = 70

Aliter :

Here, n = 13, x = 70

m =7, y = 65

m = 7, z = 75

Seventh result = m (y + z) – nx

= 7 (65 + 75) – 13 × 70

= 7 × (140) – 910

= 980 – 910 = 70

Answer: (d)

Let three numbers be a,b and c respectively.

∴ a + b + c = 16 × 3 = 48 ---(i)

b + c + 20 = 15 × 3 = 45

⇒ b + c = 45 – 20 = 25 ---(ii)

By equation (i) - (ii),

a = 48 – 25 = 23

Aliter : Using Rule 16,

Here, n = 3, F = 16, L = 15

l = 20, f= ?

f – l= n (F – L)

f – 20= 3 (16 – 15)

f = 3 + 20

f = 23