model 2 average of consecutive numbers Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 9 EXERCISES
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Basic Average Questions Practice Test, Shortcuts, Tricks, PDF »
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New Average Aptitude MCQ Average of Consecutive Numbers »
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Top 99+ Average Aptitude: Twice, One Third of Numbers MCQ »
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New +99 Average Aptitude MCQ Find nth Average of Numbers »
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99+ Average Aptitude Find New Average from Error MCQ Test »
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Top 99+ Aptitude MCQ Test on Average With Excluded Number »
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Top 99+ Aptitude Average on Ages & Weights MCQ Test Quiz »
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Top Aptitude Average MCQ Find Monthly Income for Average »
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Top 149+ Aptitude Average on Cricket & Exam MCQ Test Quiz »
The following question based on average topic of quantitative aptitude
(a) 18
(b) 15
(c) 12
(d) 21
The correct answers to the above question in:
Answer: (b)
Required average
= ${3(1+2+3+…+9)}/9$
= ${9×10}/{2×3}$ = 15
Aliter : Using Rule 9,
Here, n = 9, x = 3
Average = x$({1+n}/2)$
= 3$({1+9}/2)$ = 15
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Read more consecutive numbers Based Quantitative Aptitude Questions and Answers
Question : 1
Eight consecutive numbers are given. If the average of the two numbers that appear in the middle is 6, then the sum of the eight given numbers is
a) 48
b) 36
c) 64
d) 54
Answer »Answer: (a)
Let the first number be x.
∴ x + 3 + x + 4 = 2 × 6
⇒ 2x + 7 = 12
⇒ 2x = 5 ⇒ x =$5/2$
∴ x + (x + 1) + ....... + (x + 7) = 8x + 28
= 8×$5/2$+ 28 = 20 + 28 = 48
Question : 2
If the average of eight consecutive even numbers be 93, then the greatest number among them is
a) 98
b) 102
c) 86
d) 100
Answer »Answer: (d)
Average of 8 consecutive even numbers = 93
∴ Fifth number = 93 + 1 = 94
∴ Largest number = 94 + 6 = 100
Question : 3
The average of five consecutive positive integers is n. If the next two integers are also included, the average of all these integers will
a) increase by 2
b) remain the same
c) increase by 1
d) increase by 1.5
Answer »Answer: (c)
Five consecutive integers are :
x, x + 1, x + 2, x + 3 and x + 4
∴ Their average
= ${x+x+1+x+2+x+3+x+4}/5$
= ${5x+10}/5$ = x+2
New average
= ${(5x+10)+x+5+x+6}/7$
= ${7x+21}/7$= x + 3
Difference = x + 3 – x – 2 = 1
Question : 4
The average of 25 consecutive odd integers is 55. The highest of these integers is
a) 109
b) 155
c) 105
d) 79
Answer »Answer: (d)
Average of 25 consecutive odd numbers = 55
∴ Mid number i.e. 13th number = 55
∴ 25th number = 55 + 2 × 12
= 55 + 24 = 79
Question : 5
The average of first nine prime numbers is
a) 11$1/9$
b) 11$2/9$
c) 11
d) 9
Answer »Answer: (a)
Using Rule 1,
Average of numbers = ${x_1+x_2+…+x_n}/n$
The required average
=${2+3+5+7+11+13+17+19+23}/9$
=$100/9$ = 11 $1/9$
Question : 6
The sum of three consecutive even numbers is 28 more than the average of these three numbers. Then the smallest of these three numbers is
a) 16
b) 14
c) 12
d) 6
Answer »Answer: (c)
Let three consecutive even numbers be x, x + 2 and x + 4. According to the question,
(x + x + 2 + x + 4) – ${x+x+2+x+4}/3$= 28
⇒ (3x + 6) – ${3x+6}/3$ = 28
⇒ (3x + 6) – (x + 2) = 28
⇒ 3x + 6 – x – 2 = 28
⇒ 2x + 4 = 28
⇒ 2x = 28 – 4 = 24
⇒ x = $24/2$ = 12
GET average PRACTICE TEST EXERCISES
model 1 basic average questions
model 2 average of consecutive numbers
model 3 twice, thrice, one third etc. of numbers
model 4 find nth average from 1st & last number
model 5 find new average from error
model 6 find average of excluded number
model 7 average on ages/weight
model 8 find monthly income
model 9 average on cricket/exam
average Shortcuts and Techniques with Examples
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model 1 basic average questions
Defination & Shortcuts … -
model 2 average of consecutive numbers
Defination & Shortcuts … -
model 3 twice, thrice, one third etc. of numbers
Defination & Shortcuts … -
model 4 find nth average from 1st & last number
Defination & Shortcuts … -
model 5 find new average from error
Defination & Shortcuts … -
model 6 find average of excluded number
Defination & Shortcuts … -
model 7 average on ages/weight
Defination & Shortcuts … -
model 8 find monthly income
Defination & Shortcuts … -
model 9 average on cricket/exam
Defination & Shortcuts …
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