model 3 combination of si & ci Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 6 EXERCISES
-
500+ Basic Compound Interest MCQs Aptitude Practice Test »
-
Top 499+ Compound Interest MCQs For BANK SSC UPSC Railway »
-
New 455+ Compound Interest Problems Solution for BANK SSC »
-
Top 399+ Compound Interest Questions for UPSC TNPSC Exams »
-
Top 599+ Compound Interest Practice MCQs For SBI IBPS RBI »
-
Top 489+ Compound Interest Practice Sums For All SSC Exam »
The following question based on compound interest topic of quantitative aptitude
(a) Rs.2,250
(b) Rs.2,500
(c) Rs.2,360
(d) Rs.2,400
The correct answers to the above question in:
Answer: (d)
C.I.= P$(1 + r/100)^t$ - P
2448 = P$[(1 + r/100)^t - 1]$
or 2448 = P$[(1 + 4/100)^2 - 1]$
2448 = P$[676/625 - 1]$
2448 = P$[51/625]$
P = ${2448 × 625}/51$ = Rs.30,000
S.I. = ${30000 × 4 × 2}/100$ = Rs.2400
Using Rule 10,
Here, C.I. = Rs.2448, R = 4%, S.I. = ?
C.I.= S.I.$(1 + R/200)$
2448 = S.I.$(1 + 4/200)$
2448 = S.I.$(1 + 1/50)$
2448 = S.I.$(51/50)$
S.I. = ${2448 × 50}/51$ = Rs.2400
Discuss Form
Read more combination of si and ci Based Quantitative Aptitude Questions and Answers
Question : 1
A man borrowed some money from a private organisation at 5% simple interest per annum. He lended this money to another person at 10% compound interest per annum, and made a profit of Rs.26,410 in 4 years. The man borrowed
a) Rs.100000
b) Rs.200000
c) Rs.132050
d) Rs.150000
Answer »Answer: (a)
Let the principal be Rs.P. For 4 years,
S.I. = $\text"Principal × Time × Rate"/100$
= ${P × 4 × 5}/100$ = Rs.$P/5$
C.I. = P$[(1 + R/100)^T - 1]$
= P$[(1 + 10/100)^4 - 1]$
= P$[(11/10)^4 - 1]$
= P$(14641/10000 - 1) = {4641P}/10000$
According to the question,
${4641P}/10000 - P/5$ = 26410
${4641P - 2000P}/10000$ = 2641
${2641P}/10000$ = 2641
P = Rs.10000
Question : 2
The compound interest on a certain sum of money for 2 years at 5% per annum is Rs.410. The simple interest on the same sum at the same rate and for the same time is
a) Rs.405
b) Rs.400
c) Rs.350
d) Rs.300
Answer »Answer: (b)
Compound interest = P $[(1 + R/100)^T - 1]$
410 = P$[(1 + 5/100)^2 - 1]$
410 = P$[(1 + 1/20)^2 - 1]$
410 = P$[(21/20)^2 - 1]$
410 = P$(441/400 - 1)$
410 = P$(41/400)$
P = ${410 × 400}/41$ = Rs.4000
S.I. = $\text"Principal × Time × Rate"/100$
= ${4000 × 2 × 5}/100$ = Rs.400
Using Rule 10,
Here, C.I. = Rs.410, R = 5%, S.I. = ?
C.I. = S.I.$(1 + R/200)$
410 = S.I.$(1 + 5/200)$
410 = S.I.$(205/200)$
S.I. = ${410 × 200}/205$ = Rs.400
Question : 3
If the compound interest on a certain sum for two years at 12% per annum is Rs.2,544, the simple interest on it at the same rate for 2 years will be
a) Rs.2,440
b) Rs.2,400
c) Rs.2,480
d) Rs.2,500
Answer »Answer: (b)
C.I. = P$[(1 + R/100)^T - 1]$
2544 = P$[(1 + 12/100)^2 - 1]$
2544 = P$[(28/25)^2 - 1]$
2544 = P$(784/625 - 1)$
2544 = P$({784 - 625}/625)$
2544 = ${P × 159}/625$
P = ${2544 × 625}/159$ = Rs.10000
S.I. = ${P × R × T}/100$
= ${10000 × 2 × 12}/100$ = Rs.2400
Using Rule 10,
Here, C.I. = Rs.2544, R = 12%, S.I. = ?
C.I. = S.I.$(1 + R/200)$
2544 = S.I.$(1 + 12/200)$
2544 = S.I.$(212/200)$
S.I. = ${2544 × 200}/212$ = Rs.2400
Question : 4
The simple interest and compound interest (compounded annually) on a certain sum of money with a given rate for a period of 2 years are Rs.900 and Rs.954 respectively. The sum of money is
a) Rs.3750
b) Rs.3700
c) Rs.3850
d) Rs.3650
Answer »Answer: (a)
Difference of CI and SI for two years
= Rs.(954 - 900) = Rs.54
Sum= Difference in CI and SI × $(100/{Rate})^2$
Rate = ${2 × \text"Difference" × 100}/\text"Simple interest"$
= ${2 × 5400}/900 = 12%$
Sum = 54 × $(100/12)^2$
= $54 × 25/3 × 25/3$ = Rs.3750
Using Rule 10,
C.I. = Rs.954, S.I.=Rs.900, P=?
C.I.= S.I.$(1 + R/200)$
954 = 900$(1 + R/200)$
$954/900 = 1 + R/200$
$954/900 - 1 = R/200$
${954 - 900}/900 = R/200$
$54/9 = R/2$
R = 12%
Now S.I. = ${P × R × T}/100$
900 = ${P × 12 × 2}/100$
P = Rs.3750
compound interest Shortcuts and Techniques with Examples
-
model 1 basic compound interest using formula
Defination & Shortcuts … -
model 2 at ci sum becomes ‘n’ times after ‘t’ years
Defination & Shortcuts … -
model 3 combination of si & ci
Defination & Shortcuts … -
model 4 difference in ci & si
Defination & Shortcuts … -
model 5 ci with instalments
Defination & Shortcuts … -
model 6 comparing sum in different years
Defination & Shortcuts …
Verbal Reasoning
Question & Answer Quiz
Non Verbal Reasoning
Question & Answer Quiz
Quantitative Aptitude
Question & Answer Quiz
Computer MCQ
Question & Answer Quiz
General English
Question & Answer Quiz
History GK
Question & Answer Quiz
Polity GK
Question & Answer Quiz
Geography GK
Question & Answer Quiz
Economy GK
Question & Answer Quiz
General Awareness GK
Question & Answer Quiz
Recently Added Subject & Categories For All Competitive Exams
New 100+ Compound Interest MCQ with Answers PDF for IBPS
Compound Interest verbal ability questions and answers solutions with PDF for IBPS RRB PO. Aptitude Objective MCQ Practice Exercises all competitive exams
Continue Reading »
100+ Mixture and Alligation MCQ Questions PDF for IBPS
Most importantly Mixture and Alligation multiple choice questions and answers with PDF for IBPS RRB PO. Aptitude MCQ Practice Exercises all Bank Exams
Continue Reading »
IBPS Profit and Loss Questions Solved Problems with PDF
Most important Profit and Loss multiple choice questions and answers with PDF for IBPS RRB PO. 100+ Aptitude MCQ Practice Exercises all competitive exams
Continue Reading »
100+ Average Aptitude Questions Answers solutions MCQ PDF
New Average multiple choice questions and answers with PDF for IBPS RRB PO. 100+ Quantitative Aptitude MCQ Practice Exercises all competitive exams
Continue Reading »