model 1 basic number system Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (c)

(n – 1) is odd

⇒ (n – 1) – 2 & (n – 1) + 2 are odd.

⇒ (n – 3) and (n + 1) are odd.

Answer: (c)

Option a) 1 + 3 = 4, 3 + 5 = 8

Option b) 1 - 3 = 2, 3 - 5 = 2

Option c)  1 x 3 = 3,  3 x 5 = 15

∴ Option (C) is Correct.

Answer: (a)

Let for example:

n=3 p=5

Option a) 3 + 5 = 8 (even number)

Option b) 3 + 5 + 1 = 9 (odd number)

Option c) 3 x 5 + 2 = 17 (odd number)

Option d) 3 x 5  = 3  (odd number)

Answer: (d)

In this problem, the digits of the number from the left are x, y, z and w respectively.

So, x is at thousands places, y is at hundreds of places, z is at tens place and w is at ones place.

Thus, the required number be

= (1000×x) + (100×y) + (10×z) + (1×w)

= (1000x + 100y + 10z + w)

Answer: (d)

In this problem, the digits of the number from the left are x, y and z respectively.

So, x is at hundreds places, y is at tens place and z is at ones place.

Thus, the required number be

= (100×x) + (10×y) + (1×z)

= (100x + 10y + z)