type 1 basic concepts of ratio & proportion Section-Wise Topic Notes With Detailed Explanation And Example Questions
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The following question based on ratio & proportion topic of quantitative aptitude
(a) Rs.2500, Rs.2000, Rs.1700
(b) Rs.2200, Rs.3000, Rs.1000
(c) Rs.3500, Rs.1500, Rs.1200
(d) Rs.3000, Rs.2000, Rs.1200
The correct answers to the above question in:
Answer: (d)
Ratio = $1/2 : 1/3 : 1/5$
= $1/2 × 30 : 1/3 × 30 : 1/5$ × 30
= 15 : 10 : 6
Sum of the ratios
= 15 + 10 + 6 = 31
First part
= Rs.$15/31$ × 6200 = Rs.3000
Second part
= Rs.$10/31$ × 6200 = Rs.2000
Third part
= Rs.$6/31$ × 6200 = Rs.1200
Discuss Form
Read more basic concepts of ratio and proportion Based Quantitative Aptitude Questions and Answers
Question : 1
If A : B = $1/2 : 3/8, B : C = 1/3 : 5/9 and C : D = 5/6 : 3/4$, then the ratio A : B : C : D is
a) 8 : 6 : 10 : 9
b) 4 : 6 : 8 : 10
c) 6 : 8 : 9 : 10
d) 6 : 4 : 8 : 10
Answer »Answer: (a)
A : B = $1/2 : 3/8$ =4 : 3 = 8 : 6
B : C = $1/3 : 5/9$ = 3 : 5 = 6 : 10
C : D = $5/6 : 3/4$ = 10 : 9
A : B : C : D = 8 : 6 : 10 : 9
Question : 2
If a : b = c : d = e : f = 1 : 2, then ( 3a + 5c +7e): (3b + 5d + 7 f ) is equal to
a) 1 : 4
b) 1 : 2
c) 2 : 1
d) 8 : 7
Answer »Answer: (b)
$a/b = c/d = e/f = 1/2$
${3a}/{3b} = {5c}/{5d} = {7e}/{7f} = 1/2$
${3a+ 5c+7e}/{3b +5d +7f} = 1/2$ = 1 : 2
Question : 3
If a : b = c : d, then ${ma+ nc}/{mb +nd}$ is not equal to
a) ${a +c}/{b +d}$
b) ${c - a}/{b - d}$
c) $c/d$
d) $a/b$
Answer »Answer: (a)
a : b = c : d
$a/b = c/d = {ma}/{mb} = {nc}/{nd}$
${a + c}/{b + d} = {ma + nc}/{mb + nd}$
Question : 4
If a : b : c = 2 : 3 : 4 and 2a - 3b + 4c = 33, then the value of c is
a) 12
b) $66/7$
c) 9
d) 6
Answer »Answer: (a)
a : b : c = 2 : 3 : 4
$a/2 = b/3 =c/4$ = k (let)
a = 2k, b = 3k, and c = 4k
Given 2a - 3b + 4c = 33
2 × 2k - 3×3k + 4 ×4k = 33
4k - 9k + 16k = 33
11k = 33 ⇒ k = $33/11$ = 3
c = 4k = 4×3 = 12
Question : 5
If a : b = 7 : 9 and b : c =15 : 7, then what is a : c?
a) 7 : 21
b) 7 : 15
c) 3 : 5
d) 5 : 3
Answer »Answer: (d)
a : c = (a : b) × (b : c)
=$7/9 ×15/7 = 15/9$ = 5 : 3
Using Rule 18If A:B = x:y and B:C = p:q then(i) A:C = xp : yq(ii) A:B:C = (x:y) × p:qy =xp:yp:qy It is done as follows:A:B = x:y B:C = p:qA:B:C = xp:yp:qy
A : C = 7 × 15 : 9 × 7 = 5 : 3
GET ratio & proportion PRACTICE TEST EXERCISES
type 1 basic concepts of ratio & proportion
type 2 age based ratio & proportion problems
type 3 addition subtraction product on ratio & proportion
type 4 income & expenditure based ratio & proportion problems
type 5 shares & partnership based ratio & proportion problems
type 6 fractions based ratio & proportion problems
type 7 finding sum difference product based ratio & proportion problems
type 8 alligation & mixtures based ratio & proportion problems
type 9 coins & rupees based ratio & proportion problems
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