model 9 average on cricket/exam Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 9 EXERCISES
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Basic Average Questions Practice Test, Shortcuts, Tricks, PDF »
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New Average Aptitude MCQ Average of Consecutive Numbers »
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Top 99+ Average Aptitude: Twice, One Third of Numbers MCQ »
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New +99 Average Aptitude MCQ Find nth Average of Numbers »
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99+ Average Aptitude Find New Average from Error MCQ Test »
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Top 99+ Aptitude MCQ Test on Average With Excluded Number »
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Top 99+ Aptitude Average on Ages & Weights MCQ Test Quiz »
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Top Aptitude Average MCQ Find Monthly Income for Average »
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Top 149+ Aptitude Average on Cricket & Exam MCQ Test Quiz »
The following question based on average topic of quantitative aptitude
(a) 170
(b) 174
(c) 165
(d) 172
The correct answers to the above question in:
Answer: (b)
Let the highest score of cricketer be x runs.
∴ His lowest score = (x – 172) runs
According to the question, 38 × 48 + x + x – 172 = 40 × 50
⇒ 1824 – 172 + 2x = 2000
⇒ 1652 + 2x = 2000
⇒ 2x = 2000 – 1652 = 348
∴ x = 348 2 = 174 runs
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Read more based on cricket exam Based Quantitative Aptitude Questions and Answers
Question : 1
A cricketer, whose bowling average was 12.4 runs/wicket takes 5 wickets for 22 runs in a match, thereby decreases his average by 0.4. The number of wickets, taken by him before this match was :
a) 87
b) 105
c) 78
d) 95
Answer »Answer: (d)
Let the number of wickets before the last match be x.
According to the question,
12.4x + 22 = (x + 5 ) × 12
⇒ 12.4x + 22 = 12x + 60
⇒ 12.4x – 12x = 60 – 22
⇒ 0.4x = 38
⇒ x = $38/{0.4}$ =$380/4$ = 95
Question : 2
The average of runs scored by a player in 10 innings is 50. How many runs should he score in the 11th innings so that his average is increased by 2 runs ?
a) 72 runs
b) 54 runs
c) 80 runs
d) 60 runs
Answer »Answer: (a)
Let the number of runs scored in 11th innings be x.
∴ 10 × 50 + x = 11 × 52
⇒ 500 + x = 572
⇒ x = 572 – 500 = 72 runs
Aliter : Using Rule 18,
If in the group of N persons, a new person comes at the place of a person of 'T’ years, so that average age,
increases by 't’ years
Then, the age of the new person = T + N.t.
Here, T = 50, N = (10 + 1) = 11, t = 2
Required Runs = T + Nt
= 50 + 11 × 2 = 72
Question : 3
The average run of a player is 32 out of 10 innings. How many runs must he make in the next innings so as to increase his average by 6 ?
a) 40
b) 98
c) 38
d) 6
Answer »Answer: (b)
Runs scored in the next innings = x (let)
According to the question,
10 × 32 + x = 11 × 38
⇒ 320 + x = 418
⇒ x = 418 – 320 = 98
Aliter : Using Rule 18,
If in the group of N persons, a new person comes at the place of a person of 'T’ years, so that average age,
increases by 't’ years
Then, the age of the new person = T + N.t.
Here, T = 32, N= (10 + 1) = 11, t = 6
Required Runs = T + Nt
= 32 + 11 × 6
= 32 + 66 = 98
GET average PRACTICE TEST EXERCISES
model 1 basic average questions
model 2 average of consecutive numbers
model 3 twice, thrice, one third etc. of numbers
model 4 find nth average from 1st & last number
model 5 find new average from error
model 6 find average of excluded number
model 7 average on ages/weight
model 8 find monthly income
model 9 average on cricket/exam
average Shortcuts and Techniques with Examples
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model 1 basic average questions
Defination & Shortcuts … -
model 2 average of consecutive numbers
Defination & Shortcuts … -
model 3 twice, thrice, one third etc. of numbers
Defination & Shortcuts … -
model 4 find nth average from 1st & last number
Defination & Shortcuts … -
model 5 find new average from error
Defination & Shortcuts … -
model 6 find average of excluded number
Defination & Shortcuts … -
model 7 average on ages/weight
Defination & Shortcuts … -
model 8 find monthly income
Defination & Shortcuts … -
model 9 average on cricket/exam
Defination & Shortcuts …
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