model 9 average on cricket/exam Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 9 EXERCISES
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Top 149+ Aptitude Average on Cricket & Exam MCQ Test Quiz »
The following question based on average topic of quantitative aptitude
(a) 39
(b) 87
(c) 13
(d) 49
The correct answers to the above question in:
Answer: (a)
Extra runs = 12 × 2 = 24
∴ Required average = 63 – 24 = 39
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Read more based on cricket exam Based Quantitative Aptitude Questions and Answers
Question : 1
A cricketer had a certain average of runs for his 64 innings. In his 65th innings, he is bowled out for no score on his part. This brings down his average by 2 runs. His new average of runs is
a) 128
b) 68
c) 130
d) 70
Answer »Answer: (a)
Let the cricketer’s average of runs for his 64 innings be x runs.
∴ Total number of runs in 64 innings = 64x
According to the question,
${64x+0}/65$ = x-2
⇒ 64x = 65x – 130
⇒ x = 130
∴ New average of runs = x – 2
= 130– 2 = 128
Question : 2
The average of runs scored by a cricketer in his 99 innings is 99. How many runs will he have to score in his 100th innings so that his average of runs in 100 innings may be 100?
a) 99
b) 101
c) 100
d) 199
Answer »Answer: (d)
Number of runs scored in 100th innings
= 100 × 100 – 99 × 99
= 10000 – 9801 = 199
OR
Increase in average = 1 run
∴ Runs scored in 100th innings = 100 + 99 = 199
Question : 3
A cricketer whose bowling average is 24.85, runs per wicket, takes 5 wickets for 52 runs and thereby decreases his average by 0.85. The number of wickets taken by him till the last match was :
a) 72
b) 96
c) 64
d) 80
Answer »Answer: (d)
Let the no. of wickets taken till the last match be n.
∴ Total runs at 24.85 runs per wicket = 24.85n
Total runs after the current match = 24.85n + 52
Total no. of wickets after the current match = n + 5
Bowling Average after the current match
⇒ ${24.8n+52}/{n+5}$ = 24.85 – 0.85
∴ ${24.8n+52}/{n+5}$ = 24
or 24.85n + 52 = 24n + 120
or 0.85n = 120 – 52
or n = $68/{0.85}$ = 80
Question : 4
The averages of runs scored by a cricket player in 11 innings is 63 and the average of his first six innings is 60 and the average of last six innings is 65. Find the runs scored by him in the sixth innings.
a) 54
b) 57
c) 60
d) 67
Answer »Answer: (b)
Runs scored by the cricketer in the 6th innings
= 6 × 60 + 6 × 65 – 11 × 63
= 360 + 390 – 693 = 57
Question : 5
A cricketer whose bowling average is 12.4 runs per wicket, takes 5 wickets for 26 runs and thereby decreases his average by 0.4. The number of wickets taken by him till the last match was
a) 72
b) 85
c) 64
d) 80
Answer »Answer: (b)
Required number of wickets = x (let)
According to question,
12.4 × x + 26 = (x + 5) (12.4 – 0.4) = (x + 5) × 12
⇒ 12.4x + 26 = 12x + 60
⇒ 12.4x – 12x = 60 – 26
⇒ 0.4x = 34
⇒ x = $34/{0.4}$ = $340/4$ = 85
Question : 6
A batsman makes a score of 87 runs in the 17th innings and thus increased his average by 3. Find his average after 17th innings.
a) 87
b) 84
c) 39
d) 90
Answer »Answer: (c)
Average runs in 16 innings = 87 – 17 × 3 = 87 – 51 = 36
∴ Required average = 36 + 3 = 39 runs
GET average PRACTICE TEST EXERCISES
model 1 basic average questions
model 2 average of consecutive numbers
model 3 twice, thrice, one third etc. of numbers
model 4 find nth average from 1st & last number
model 5 find new average from error
model 6 find average of excluded number
model 7 average on ages/weight
model 8 find monthly income
model 9 average on cricket/exam
average Shortcuts and Techniques with Examples
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model 1 basic average questions
Defination & Shortcuts … -
model 2 average of consecutive numbers
Defination & Shortcuts … -
model 3 twice, thrice, one third etc. of numbers
Defination & Shortcuts … -
model 4 find nth average from 1st & last number
Defination & Shortcuts … -
model 5 find new average from error
Defination & Shortcuts … -
model 6 find average of excluded number
Defination & Shortcuts … -
model 7 average on ages/weight
Defination & Shortcuts … -
model 8 find monthly income
Defination & Shortcuts … -
model 9 average on cricket/exam
Defination & Shortcuts …
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