type 8 alligation & mixtures based ratio & proportion problems Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on ratio & proportion topic of quantitative aptitude

Questions : Vessels A and B contain mixtures of milk and water in the ratios 4 : 5 and 5 : 1 respectively. In what ratio should quantities of mixture be taken from A and B to form a mixture in which milk to water is in the ratio 5 : 4?

(a) 5 : 2

(b) 2 : 3

(c) 4 : 3

(d) 2 : 5

The correct answers to the above question in:

Answer: (a)

First of all we write the fraction of milk present in three mixtures.

In A; $4/9$ and In B; $5/6$

In combination of A and B; $5/9$

From alligation rule,

= $5/18 : 1/9$

$5/18 : 2/18$ ⇒ 5 : 2

So, ratio of

A : B = 5 : 2

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Read more alligation and mixtures problems Based Quantitative Aptitude Questions and Answers

Question : 1

Two vessels A and B contain milk and water mixed in the ratio 4 : 3 and 2 : 3. The ratio in which these mixtures be mixed to form a new mixture containing half milk and half water is

a) 5 : 6

b) 4 : 3

c) 6 : 5

d) 7 : 5

Answer: (d)

Required ratio

= $1/10 : 1/14$ = 7 : 5

Question : 2

There is 81 litres pure milk in a container. One-third of milk is replaced by water in the container. Again one-third of mixture is extracted and equal amount of water is added. What is the ratio of milk to water in the new mixture?

a) 2 : 1

b) 4 : 5

c) 1 : 1

d) 1 : 2

Answer: (b)

Quantity of milk in the last

= $81(1 - 27/81)^2 = 81(1 - 1/3)^2$

= $81 × 2/3 × 2/3$ = 36

Quantity of water in the last

= 81 - 36 = 45

Ratio = $36/45 = 4/5 = 4 : 5$

Question : 3

In a 729 litres mixture of milk and water, the ratio of milk to water is 7 : 2. To get a new mixture containing milk and water in the ratio 7 : 3, the amount of water to be added is

a) 56 litres

b) 50 litres

c) 71 litres

d) 81 litres

Answer: (d)

Quantity of milk in 729 litres of mixture

= $7/9 × 729$ = 567 litres

Quantity of water

= (729 - 567) litres = 162 litres.

Let x litres of water is mixed to get the required ratio of 7 : 3

$567/{162 + x} =7/3$

7x + 1134 = 1701

7x = 1701 - 1134 = 567

$x = 567/7$ = 81 litres

Question : 4

A and B are two alloys of gold and copper prepared by mixing metals in ratios 7 : 2 and 7 : 11 respectively. If equal quantities of the alloys are melted to form a third alloy C, the ratio of gold and copper in C will be ;

a) 9 : 5

b) 5 : 7

c) 5 : 9

d) 7 : 5

Answer: (d)

Gold = $7/9 : 7/18 = 14/18 : 7/18$

Gold in new mixture

= 14 + 7 = 21

and copper = 18 × 2 - 21

= 36 - 21 = 15

Required ratio

= 21 : 15 = 7 : 5

Question : 5

A jar contained a mixture of two liquids A and B in the ratio 4 : 1. When 10 litres of the mixture was taken out and 10 litres of liquid B was poured into the jar, this ratio became 2 : 3. The quantity of liquid A contained in the jar initially was

a) 16 litres

b) 40 litres

c) 8 litres

d) 4 litres

Answer: (b)

Let the initial quantity of liquids A and B in the jar be 4x and x litres respectively.

After taking out 10 litres of the mixture,

Liquid A

= $4x - 4/5 × 10 = (4x - 8)$ litres

Liquid B

= $4x - 1/5 ×10 = (4x - 2)$ litres

After pouring 10 litres of liquid B,

${4x - 8}/{4x - 2 + 10} = 2/3$

12x - 24 = 8x + 16

4x = 40

$x = 40/4$ = 10

Quantity of liquid A = 4x

= 4 × 10 = 40 litres

Question : 6

In 40 litres mixture of milk and water the ratio of milk to water is 7 : 1. In order to make the ratio of milk and water 3 : 1, the quantity of water (in litres) that should be added to the mixture will be

a) 6$2/3$

b) 6$3/4$

c) 6$1/2$

d) 6

Answer: (a)

In 40 litres mixture,

Quantity of milk

= $7/8$ × 40 = 35 litres

Quantity of water = 5 litres

Let x litres of water be mixed

$35/{5 + x} =3/1$

3x + 15 = 35

3x = 20

$x = 20/3 = 6{2}/3$ litres

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