type 8 alligation & mixtures based ratio & proportion problems Section-Wise Topic Notes With Detailed Explanation And Example Questions
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The following question based on ratio & proportion topic of quantitative aptitude
(a) 60 litres
(b) 80 litres
(c) 40 litres
(d) 20 litres
The correct answers to the above question in:
Answer: (c)
Let the quantity of additional milk added = x litres
In the mixture of 200 litres,
Quantity of milk
= $17/20 × 200$ = 170 litres
Quantity of water = 30 litres
According to the question,
${170 + x}/30 = 7/1$
170 + x = 210
x = 210 - 170 = 40 litres
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Read more alligation and mixtures problems Based Quantitative Aptitude Questions and Answers
Question : 1
A mixture contains spirit and water in the ratio 3 : 2. If it contains 3 litres more spirit than water, the quantity of spirit in the mixture is
a) 8 litres
b) 9 litres
c) 12 litres
d) 10 litres
Answer »Answer: (b)
Let the amount of water be x litres.
Then, ${x + 3}/x = 3/2$
or 2x + 6 = 3x
or x = 6
The quantity of spirit in the mixture
= x + 3 = 6 + 3 = 9 litres
Question : 2
In 80 litres mixture of milk and water the ratio of amount of milk to that of amount of water is 7 : 3. In order to make this ratio 2 : 1, how many litres of water should be added ?
a) 8
b) 4
c) 6
d) 5
Answer »Answer: (b)
Quantity of milk
= $7/10 × 80 = 56$ litres
Quantity of water
= $3/10 × 80$ = 24 litres
Let x litre water be added Then,
$56/{24 + x} = 2/1$
24 + x =28 ⇒ x = 4 litres
Question : 3
In 40 litres mixture of milk and water the ratio of milk to water is 7 : 1. In order to make the ratio of milk and water 3 : 1, the quantity of water (in litres) that should be added to the mixture will be
a) 6$2/3$
b) 6$3/4$
c) 6$1/2$
d) 6
Answer »Answer: (a)
In 40 litres mixture,
Quantity of milk
= $7/8$ × 40 = 35 litres
Quantity of water = 5 litres
Let x litres of water be mixed
$35/{5 + x} =3/1$
3x + 15 = 35
3x = 20
$x = 20/3 = 6{2}/3$ litres
Question : 4
A container contains 60 kg of milk. From this container 6 kg of milk was taken out and replaced by water. This process was repeated further two times. The amount of milk left in the container is
a) 43.74 kg
b) 47.6 kg
c) 39.64 kg
d) 34.24 kg
Answer »Answer: (a)
Amount of milk left
= Initial amount ×
$(1-\text”Amount taken out in each operation”/\text”Initial amount”)^3$
= $60(1 - 6/60)^3$
= $60(1 - 1/10)^3$
= $60 × 9/10 × 9/10 × 9/10$
= 43.74 kg.
Question : 5
Two alloys are both made up of copper and tin. The ratio of copper and tin in the first alloy is 1 : 3 and in the second alloy is 2 : 5. In what ratio should the two alloys be mixed to obtain a new alloy in which the ratio of tin and copper be 8 : 3 ?
a) 3 : 8
b) 5 : 11
c) 4 : 7
d) 3 : 5
Answer »Answer: (c)
By rule of alligation
Required ratio
= $1/77 : 1/44$ = 4 7
Question : 6
A mixture contains alcohol and water in the ratio 4 : 3. If 5 litres of water is added to the mixture, the ratio becomes 4 : 5. The quantity of alcohol in the given mixture is
a) 15 litres
b) 10 litres
c) 4 litres
d) 3 litres
Answer »Answer: (b)
In original mixture,
Alcohol = 4x litres
Water = 3x litres
On adding 5 litres of water,
${4x}/{3x + 5} = 4/5$
20x = 12x + 20
8x = 20
$x = 20/8 = 5/2$
Quantity of alcohol
= $4x = 4 × 5/2$ = 10 litres
GET ratio & proportion PRACTICE TEST EXERCISES
type 1 basic concepts of ratio & proportion
type 2 age based ratio & proportion problems
type 3 addition subtraction product on ratio & proportion
type 4 income & expenditure based ratio & proportion problems
type 5 shares & partnership based ratio & proportion problems
type 6 fractions based ratio & proportion problems
type 7 finding sum difference product based ratio & proportion problems
type 8 alligation & mixtures based ratio & proportion problems
type 9 coins & rupees based ratio & proportion problems
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