type 8 alligation & mixtures based ratio & proportion problems Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on ratio & proportion topic of quantitative aptitude

Questions : A mixture contains alcohol and water in the ratio 4 : 3. If 5 litres of water is added to the mixture, the ratio becomes 4 : 5. The quantity of alcohol in the given mixture is

(a) 15 litres

(b) 10 litres

(c) 4 litres

(d) 3 litres

The correct answers to the above question in:

Answer: (b)

In original mixture,

Alcohol = 4x litres

Water = 3x litres

On adding 5 litres of water,

${4x}/{3x + 5} = 4/5$

20x = 12x + 20

8x = 20

$x = 20/8 = 5/2$

Quantity of alcohol

= $4x = 4 × 5/2$ = 10 litres

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Read more alligation and mixtures problems Based Quantitative Aptitude Questions and Answers

Question : 1

Two alloys are both made up of copper and tin. The ratio of copper and tin in the first alloy is 1 : 3 and in the second alloy is 2 : 5. In what ratio should the two alloys be mixed to obtain a new alloy in which the ratio of tin and copper be 8 : 3 ?

a) 3 : 8

b) 5 : 11

c) 4 : 7

d) 3 : 5

Answer: (c)

By rule of alligation

Required ratio

= $1/77 : 1/44$ = 4 7

Question : 2

A container contains 60 kg of milk. From this container 6 kg of milk was taken out and replaced by water. This process was repeated further two times. The amount of milk left in the container is

a) 43.74 kg

b) 47.6 kg

c) 39.64 kg

d) 34.24 kg

Answer: (a)

Amount of milk left

= Initial amount ×

$(1-\text”Amount taken out in each operation”/\text”Initial amount”)^3$

= $60(1 - 6/60)^3$

= $60(1 - 1/10)^3$

= $60 × 9/10 × 9/10 × 9/10$

= 43.74 kg.

Question : 3

200 litres of a mixture contains milk and water in the ratio 17 : 3. After the addition of some more milk to it, the ratio of milk to water in the resulting mixture becomes 7 : 1. The quantity of milk added to it was

a) 60 litres

b) 80 litres

c) 40 litres

d) 20 litres

Answer: (c)

Let the quantity of additional milk added = x litres

In the mixture of 200 litres,

Quantity of milk

= $17/20 × 200$ = 170 litres

Quantity of water = 30 litres

According to the question,

${170 + x}/30 = 7/1$

170 + x = 210

x = 210 - 170 = 40 litres

Question : 4

A container contains two liquids A and B in the ratio 7 : 5. When 9 litres of mixture are drawn off and the container is filled with B, the ratio of A and B becomes 1:1. How many litres of liquid A was in the container initially ?

a) 36$3/4$

b) 26$3/4$

c) 16$1/2$

d) 26

Answer: (a)

Let Liquid A = 7x litres

Liquid B = 5x litres

In 9 litres,

A = $7/12 × 9 = 21/4$ litres

B = $5/12 × 9 = 15/4$ litres

$7x - 21/4 = 5x - 15/4 + 9$

$2x = 21/4 - 15/4 + 9$

$2x = {21 - 15 + 36}/4 =42/4$

$x = 21/4$

Liquid A = $7 × 21/4$

= $147/4 = 36{3}/4$ litre

Question : 5

A can contains a mixture of two liquids A and B in the ratio 7 : 5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7 : 9. Litres of liquid A contained by the can initially was

a) 21

b) 25

c) 20

d) 10

Answer: (a)

Let A = 7x litre, B = 5x litre

In 9 litres of mixture,

A = ${7x}/{12x} × 9 = 21/4$ litres

B = ${5x}/{12x} × 9 = 15/4$ litres

In new situation,

${7x - 21/4}/{5x - 15/4 + 9} = 7/9$

${28x - 21}/{20x - 15 + 36} = 7/9$

252x - 189 = 140x + 147

112x = 336

x = 3

Initial quantity of liquid A

= 7x = 7 × 3 = 21 litres

Question : 6

There are three containers of equal capacity. The ratio of Sulphuric acid to water in the first container is 3 : 2, that in the second container is 7 : 3 and in the third container it is 11 : 4. If all the liquids are mixed together, then the ratio of Sulphuric acid to water in the mixture will be :

a) 60 : 29

b) 59 : 29

c) 61 : 28

d) 61 : 29

Answer: (d)

In the new vessel, we have.

Sulphuric acid

= $3/5 + 7/10 + 11/15$

=${18 + 21 + 22}/30 = 61/30$

Water = $2/5 + 3/10 + 4/15$

= ${12 + 9 + 8}/30 = 29/30$

Sulphuric acid : Water

= $61/30 : 29/30$= 61 : 29

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