type 8 alligation & mixtures based ratio & proportion problems Section-Wise Topic Notes With Detailed Explanation And Example Questions
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The following question based on ratio & proportion topic of quantitative aptitude
(a) 5 : 7
(b) 2 : 7
(c) 5 : 2
(d) 3 : 5
The correct answers to the above question in:
Answer: (b)
Milk in the resulting mixture = $9/13$
= ${65 - 63}/{7 × 13} = 2/{7 × 13}$
Required ratio
= $2/{7 × 13} : 1/13$ = 2 : 7
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Read more alligation and mixtures problems Based Quantitative Aptitude Questions and Answers
Question : 1
There are three containers of equal capacity. The ratio of Sulphuric acid to water in the first container is 3 : 2, that in the second container is 7 : 3 and in the third container it is 11 : 4. If all the liquids are mixed together, then the ratio of Sulphuric acid to water in the mixture will be :
a) 60 : 29
b) 59 : 29
c) 61 : 28
d) 61 : 29
Answer »Answer: (d)
In the new vessel, we have.
Sulphuric acid
= $3/5 + 7/10 + 11/15$
=${18 + 21 + 22}/30 = 61/30$
Water = $2/5 + 3/10 + 4/15$
= ${12 + 9 + 8}/30 = 29/30$
Sulphuric acid : Water
= $61/30 : 29/30$= 61 : 29
Question : 2
A can contains a mixture of two liquids A and B in the ratio 7 : 5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7 : 9. Litres of liquid A contained by the can initially was
a) 21
b) 25
c) 20
d) 10
Answer »Answer: (a)
Let A = 7x litre, B = 5x litre
In 9 litres of mixture,
A = ${7x}/{12x} × 9 = 21/4$ litres
B = ${5x}/{12x} × 9 = 15/4$ litres
In new situation,
${7x - 21/4}/{5x - 15/4 + 9} = 7/9$
${28x - 21}/{20x - 15 + 36} = 7/9$
252x - 189 = 140x + 147
112x = 336
x = 3
Initial quantity of liquid A
= 7x = 7 × 3 = 21 litres
Question : 3
A container contains two liquids A and B in the ratio 7 : 5. When 9 litres of mixture are drawn off and the container is filled with B, the ratio of A and B becomes 1:1. How many litres of liquid A was in the container initially ?
a) 36$3/4$
b) 26$3/4$
c) 16$1/2$
d) 26
Answer »Answer: (a)
Let Liquid A = 7x litres
Liquid B = 5x litres
In 9 litres,
A = $7/12 × 9 = 21/4$ litres
B = $5/12 × 9 = 15/4$ litres
$7x - 21/4 = 5x - 15/4 + 9$
$2x = 21/4 - 15/4 + 9$
$2x = {21 - 15 + 36}/4 =42/4$
$x = 21/4$
Liquid A = $7 × 21/4$
= $147/4 = 36{3}/4$ litre
Question : 4
A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup ?
a) $1/5$
b) $1/7$
c) $1/4$
d) $1/3$
Answer »Answer: (a)
Ratio = 4 : 1
Required quantity = $1/5$
Question : 5
In two alloys A and B, the ratio of zinc to tin is 5 : 2 and 3 : 4 respectively. Seven kg of the alloy A and 21 kg of the alloy B are mixed together to form a new alloy. What will be the ratio of zinc and tin in the new alloy ?
a) 2 : 3
b) 1 : 1
c) 1 : 2
d) 2 : 1
Answer »Answer: (b)
In 7 kg of alloy A,
Zinc = 5 kg, Tin = 2 kg
In 21 kg of alloy B
Zinc = ${21 × 3}/7 = 9$ kg
Tin = ${21 × 4}/7 = 12$ kg
Required ratio
= (5 + 9) : (2 + 12)
= 14 : 14 or 1 : 1
Question : 6
In a mixture of 75 litres, the ratio of milk to water is 2 : 1. The amount of water to be further added to the mixture so as to make the ratio of the milk to water 1 : 2 will be
a) 75 litres
b) 80 litres
c) 60 litres
d) 45 litres
Answer »Answer: (a)
In 75 litres of the mixture,
Milk = $2/3$ × 75 = 50 litres
Water = $1/3 × 75$ = 25 litres
Let x litres of water be added.
Then, $50/{x + 25} = 1/2$
x + 25 = 100
x = 75 litres
GET ratio & proportion PRACTICE TEST EXERCISES
type 1 basic concepts of ratio & proportion
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type 4 income & expenditure based ratio & proportion problems
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type 7 finding sum difference product based ratio & proportion problems
type 8 alligation & mixtures based ratio & proportion problems
type 9 coins & rupees based ratio & proportion problems
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