type 8 alligation & mixtures based ratio & proportion problems Section-Wise Topic Notes With Detailed Explanation And Example Questions
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The following question based on ratio & proportion topic of quantitative aptitude
(a) $3/4$
(b) $2/3$
(c) $1/3$
(d) $1/4$
The correct answers to the above question in:
Answer: (c)
Let the barrel contain 4 litres of mixture.
Wine = 3 litres
Water = 1 litre
Let x litre mixture is taken out.
Wine in (4 - x) litres mixture
= $3/4(4 - x)$
On adding x litres water, water in mixture
= $(4 - x) × 1/4 + x = 1 - x/4 + x$
= ${4 - x +4x}/4 = {4 + 3x}/4$
$3/4(4 - x) = {4 + 3x}/4$
$3 - {3x}/4 = 1 + {3x}/4$
$2 = {6x}/4$
$x = {2 × 4}/6 = 4/3$
Required answer
= ${4/3}/4 = 1/3$
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Read more alligation and mixtures problems Based Quantitative Aptitude Questions and Answers
Question : 1
In an alloy, the ratio of copper and zinc is 5 : 2. If 1.250 kg of zinc is mixed in 17 kg 500 g of alloy, then the ratio of copper and zinc will be
a) 3 : 2
b) 1 : 2
c) 2 : 3
d) 2 : 1
Answer »Answer: (d)
Weight of copper in 17kg 500 gm
i.e. 17500 gm of alloy
= $5/7$ × 17500 = 12500 gm
Weight of zinc = (17500 - 12500) = 5000 gm
1250 gm of zinc is mixed in alloy.
Total weight of zinc
= 1250 + 5000 = 6250 gm.
Required ratio
= 12500 : 6250 = 2 : 1
Question : 2
The proportion of acid and water in three samples is 2 : 1, 3 : 2 and 5 : 3. A mixture containing equal quantities of all three samples is made. The ratio of water and acid in the mixture is :
a) 227 : 120
b) 133 : 227
c) 227 : 133
d) 120 : 133
Answer »Answer: (c)
Required ratio
= $(2/3 + 3/5 + 5/8) : (1/3 + 2/5 + 3/8)$
= $({80 + 72 + 75}/120) : ({40 + 48 + 45}/120)$
= 227 : 133
Question : 3
Zinc and copper are in the ratio 5 : 3 in 400 gm of an alloy. How much of copper (in grams) should be added to make the ratio 5 : 4?
a) 72
b) 200
c) 66
d) 50
Answer »Answer: (d)
In 400 gm of alloy,
Zinc = $5/8 × 400$ = 250 gm.
Copper = $3/8 × 400 = 150$ gm.
If x gm of copper be mixed, then
$250/{150 + x} = 5/4$
750 + 5x = 1000
5x = 1000 - 750 = 250
x = 50 gm.
Question : 4
In 30 litres mixture of acid, the ratio of acid and water is 2 : 3 . What amount of water should be added to the mixture so that the ratio of acid and water becomes 2 : 5 ?
a) 18 litres
b) 12 litres
c) 15 litres
d) 10 litres
Answer »Answer: (b)
In 30 litres of mixture,
Acid = $2/5 × 30$ = 12 litres
Water = $3/5 × 100$ = 18 litres
$12/{18 + x} = 2/5$
60 = 36 + 2x
2x = 60 - 36 = 24
x = 12 litres of water.
Question : 5
A mixture of 30 litres contain milk and water in the ratio of 7 : 3. How much water should be added to it so that the ratio of milk and water becomes 3 : 7 ?
a) 56 litres
b) 63 litres
c) 49 litres
d) 40 litres
Answer »Answer: (d)
Quantity of milk in 30 litre mixture
= $30/10 × 7$ = 21litres
Quantity of water
= $30/10 × 3 =9$ litres
Suppose x litres more water is added.
According to question,
$21/{9 + x} = 3/7$
9 + x = 49
x = 40 litres
Question : 6
Zinc and copper are in the ratio of 5 : 3 in 200 gm of an alloy. How much grams of copper be added to make the ratio as 3 : 5?
a) 72
b) 66
c) $1/200$
d) 133$1/3$
Answer »Answer: (d)
Weight of zinc
= $200 × 5/8$= 125 gram
Weight of copper
= $200 × 3/8$ = 75 gram.
Let the ratio of 125 gram zinc and x gram copper be 3 : 5
= $125/x = 3/5$
$x = {125× 5}/3 = 625/3$ gram
Addition of copper in mixture
= $625/3 - 75 = {625 - 225}/3$
= $400/3 = 133{1}/3$ gram.
GET ratio & proportion PRACTICE TEST EXERCISES
type 1 basic concepts of ratio & proportion
type 2 age based ratio & proportion problems
type 3 addition subtraction product on ratio & proportion
type 4 income & expenditure based ratio & proportion problems
type 5 shares & partnership based ratio & proportion problems
type 6 fractions based ratio & proportion problems
type 7 finding sum difference product based ratio & proportion problems
type 8 alligation & mixtures based ratio & proportion problems
type 9 coins & rupees based ratio & proportion problems
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