type 8 alligation & mixtures based ratio & proportion problems Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on ratio & proportion topic of quantitative aptitude

Questions : Zinc and copper are in the ratio of 5 : 3 in 200 gm of an alloy. How much grams of copper be added to make the ratio as 3 : 5?

(a) 72

(b) 66

(c) $1/200$

(d) 133$1/3$

The correct answers to the above question in:

Answer: (d)

Weight of zinc

= $200 × 5/8$= 125 gram

Weight of copper

= $200 × 3/8$ = 75 gram.

Let the ratio of 125 gram zinc and x gram copper be 3 : 5

= $125/x = 3/5$

$x = {125× 5}/3 = 625/3$ gram

Addition of copper in mixture

= $625/3 - 75 = {625 - 225}/3$

= $400/3 = 133{1}/3$ gram.

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Read more alligation and mixtures problems Based Quantitative Aptitude Questions and Answers

Question : 1

A mixture of 30 litres contain milk and water in the ratio of 7 : 3. How much water should be added to it so that the ratio of milk and water becomes 3 : 7 ?

a) 56 litres

b) 63 litres

c) 49 litres

d) 40 litres

Answer: (d)

Quantity of milk in 30 litre mixture

= $30/10 × 7$ = 21litres

Quantity of water

= $30/10 × 3 =9$ litres

Suppose x litres more water is added.

According to question,

$21/{9 + x} = 3/7$

9 + x = 49

x = 40 litres

Question : 2

In 30 litres mixture of acid, the ratio of acid and water is 2 : 3 . What amount of water should be added to the mixture so that the ratio of acid and water becomes 2 : 5 ?

a) 18 litres

b) 12 litres

c) 15 litres

d) 10 litres

Answer: (b)

In 30 litres of mixture,

Acid = $2/5 × 30$ = 12 litres

Water = $3/5 × 100$ = 18 litres

$12/{18 + x} = 2/5$

60 = 36 + 2x

2x = 60 - 36 = 24

x = 12 litres of water.

Question : 3

A barrel contains a mixture of wine and water in the ratio 3 : 1. How much fraction of the mixture must be drawn off and substituted by water so that the ratio of wine and water in the resultant mixture in the barrel becomes 1 : 1 ?

a) $3/4$

b) $2/3$

c) $1/3$

d) $1/4$

Answer: (c)

Let the barrel contain 4 litres of mixture.

Wine = 3 litres

Water = 1 litre

Let x litre mixture is taken out.

Wine in (4 - x) litres mixture

= $3/4(4 - x)$

On adding x litres water, water in mixture

= $(4 - x) × 1/4 + x = 1 - x/4 + x$

= ${4 - x +4x}/4 = {4 + 3x}/4$

$3/4(4 - x) = {4 + 3x}/4$

$3 - {3x}/4 = 1 + {3x}/4$

$2 = {6x}/4$

$x = {2 × 4}/6 = 4/3$

Required answer

= ${4/3}/4 = 1/3$

Question : 4

The milk and water in a mixture are in the ratio 7 : 5. When 15 litres of water are added to it, the ratio of milk and water in the new mixture becomes 7 : 8. The total quantity of water in the new mixture is

a) 60 litres

b) 96 litres

c) 40 litres

d) 35 litres

Answer: (c)

Let the quantity of milk in the mixture = 7x litres and that of water = 5x litres.

According to the question,

${7x}/{5x + 15} = 7/8$

56x = 35x + 105

56 x - 35 x = 105

21x = 105

$x = 105/21$ =5

Required quantity of water

= (5x + 15) litres

= 5 × 5 + 15 = 40 litres

Question : 5

The ratio in which a man must mix rice at Rs.10.20 per kg and Rs.14.40 per kg so as to make a mixture worth Rs.12.60 per kg, is

a) 18 : 24

b) 3 : 4

c) 2 : 5

d) 4 : 3

Answer: (b)

Required ratio = 1.8 : 2.4

= 18 : 24 = 3 : 4

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