model 7 average on ages/weight Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 9 EXERCISES

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The following question based on average topic of quantitative aptitude

Questions : From a class of 42 boys, a boy aged 10 years goes away and in his place, a new boy is admitted. If on account of this change, the average age of the boys in that class increases by 2 months, the age of the newcomer is :

(a) 17 years

(b) 19 years

(c) 12 years 2 months

(d) 10 years 6 months

The correct answers to the above question in:

Answer: (a)

Age of new boy = $(10 + {2 × 42}/12)$ = 17 years

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Read more ages weights Based Quantitative Aptitude Questions and Answers

Question : 1

The present average age of a family of four members is 36 years. If the present age of the youngest member of the family be 12 years, the average age of the family at the birth of the youngest member was

a) 40 years

b) 48 years

c) 24 years

d) 32 years

Answer: (d)

Sum of the present ages of whole family = 36 × 4 = 144 years

Sum of the ages of the family at the birth of youngest member

= 144 – 4 × 12 = 96 years

∴ Required Average age =$96/3$ = 32 years

Question : 2

If out of 10 selected students for an examination, 3 were of 20 years, age, 4 of 21 and 3 of 22 years, the average age of the group is

a) 21 years

b) 22 years

c) 20 years

d) 21.5 years

Answer: (a)

Average age of the whole group

= ${3 × 20 + 4 × 21+3 × 22}/10$

= ${60 + 84 + 66}/10$ = $210/10$

= 21 years

Question : 3

Average age of 6 sons of a family is 8 years. Average age of sons together with their parents is 22 years. If the father is older than the mother by 8 years, the age of mother (in years) is :

a) 52

b) 44

c) 68

d) 60

Answer: (d)

Let the mother’s age = x years

∴ Father’s age = (x + 8) years

Sum of age of 6 sons = 8 × 6 = 48 years

Sum of age of 6 sons and parents = 22 × 8 = 176 years.

∴ Age of Parents = 176 – 48 = 128 years

⇒ x + x + 8 = 128

⇒ 2x = 120

⇒ x = 60

Hence, mother’s age = 60 years

Question : 4

The average age of a family of 10 members is 20 years. If the age of the youngest member of the family is 10 years, then the average age of the members of the family just before the birth of the youngest member was approximately

a) 12.5 years

b) 27.14 years

c) 11$1/9$ years

d) 14.28 years

Answer: (c)

Sum of the present age of 10 members

= 20 × 10 = 200 years

Total age of 9 members, 10 years ago = 100 years

Required average = $100/9$ =11$1/9$ years

Question : 5

The average age of 30 boys in a class is 15 years. One boy, aged 20 years, left the class, but two new boys came in his place whose age differ by 5 years. If the average age of all the boys now in the class becomes 15 years, the age of the younger newcomer is :

a) 15 years

b) 20 years

c) 8 years

d) 10 years

Answer: (a)

Total age of 30 boys = 30 × 15 = 450 years

One boy, aged 20 years, left the class

Now, total age of 29 boys = 450 – 20 = 430 years

Again, two new boys join the class

Then, the total age of 31 boys = 15 × 31 = 465 years

∴ Age of two new boys = 465 – 430 = 35 years

Let the individual age of two boys be x and y years

∴ x + y = 35

x – y = 5 (According to the question)

∴ 2x = 40

x = $40/2$ = 20 years

∴ y = 15 years

∴ Age of the younger new comer = 15 years

Question : 6

There are 30 students in a class. The average age of first 10 students is 12.5 years. The average age of the remaining 20 students is 13.1 years. The average age (in years) of the students of the whole class is

a) 12.7 years

b) 12.5 years

c) 12.9 years

d) 12.8 years

Answer: (c)

Using Rule 10,

( If the average of 'n1 ’ numbers is a1 and the average of 'n2 ’ numbers is a2 , then average of total numbers n1 and n2 is

Average = ${n_1a_1 + n_2a_2}/{n_1 + n_2}$ )

Average age = ${10 × 12.5 + 20 × 13.1}/{10+20}$

= ${125+262}/30$ =12.9 years

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