model 7 average on ages/weight Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 9 EXERCISES

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The following question based on average topic of quantitative aptitude

Questions : Five years ago, the average age of P, Q and R was 25 years and seven years ago, the average age of Q and R was 20 years. The present age of P is

(a) 29 years

(b) 36 years

(c) 21 years

(d) 24 years

The correct answers to the above question in:

Answer: (b)

Sum of the present age of P, Q and R

= (25 × 3 + 3 × 5) years

= (75 + 15) years = 90 years

Sum of the present age of Q and R

= (20 × 2 + 2 × 7) years = 54 years

∴ p’s present age = (90 – 54) years = 36 years

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Read more ages weights Based Quantitative Aptitude Questions and Answers

Question : 1

The average age of 40 students of a class is 15 years. When 10 new students are admitted, the average is increased by 0.2 year. The average age of the new students is :

a) 16 years

b) 15.2 years

c) 16.4 years

d) 16.2 years

Answer: (a)

Total age of 40 old students = 40 × 15 = 600 years.

Total age of 40 old and 10 new students = 50 × 15.2 = 760 years

∴ Total age of 10 new students = 760–600 = 160 years.

∴ Required average age = $160/10$ = 16 years.

Question : 2

The average age of 30 boys in a class is 15 years. One boy aged 20 years, left the class, but two new boys came in his place whose ages differ by 5 years. If the average age of all the boys now in the class still remains 15 years, the age of the younger newcomer is :

a) 15 years

b) 20 years

c) 8 years

d) 10 years

Answer: (a)

Let the age of younger boy be x years.

∴ Age of older boy = (x + 5) years.

Then, total age of 30 boys = 30 × 15 = 450 years.

Total age of 31 boys after two newcomers join &1 left

= 450 – 20 + x + x + 5

= 435 + 2x

Clearly, 435 + 2x = 31 × 15

⇒ 2x = 465 – 435

⇒ x = $30/2$ =15 years

Question : 3

The average age of a husband and wife, who were married 4 years ago, was 25 years at the time of their marriage. The average age of the family consisting of husband, wife and a child, born during the interval is 20 years today. The age of the child is

a) 2 years

b) 1 year

c) 3 years

d) 2.5 years

Answer: (a)

Sum of the present age of husband and wife

= 2 × 25 + 2 × 4 = 58 years

Sum of the present age of husband, wife and child

= 3 × 20 = 60 years

&there; Child’s present age

= 60 – 58 = 2 years

Question : 4

The average age of 5 boys is 12 years. The average age of 3 others is 16 years. The average age of all the 8 boys is :

a) 14 years

b) 13$1/2$ years

c) 13 years

d) 12$1/2$ years

Answer: (b)

Required average = ${5 × 12 + 3 × 16}/{5+3}$ =${60+48}/8$

= $108/8$ = $27/2$ = 13$1/2$ years

Question : 5

The average age of Ram and his two children is 17 years and the average age of Ram’s wife and the same children is 16 years. If the age of Ram is 33 years, the age of his wife is (in years):

a) 32

b) 31

c) 30

d) 35

Answer: (c)

Ram + two children = 51 years

His wife + two children = 48 years

∴ Ram – wife = 3 years

⇒ 33 – wife = 3 years

∴ Wife = 33 – 3 = 30 years

Question : 6

In a school, the average age of students is 6 years, and the average age of 12 teachers is 40 years. If the average age of the combined group of all the teachers and students is 7 years, then the number of students is :

a) 400

b) 396

c) 416

d) 408

Answer: (b)

Let the number of students be n. Then,

7 = ${n × 6 + 12 × 40}/{n + 12}$

⇒ 7n + 84 = 6n + 480

⇒ n = 480 – 84 = 396

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